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melisa1 [442]
3 years ago
9

A scientist analyzes four samples of compounds. He finds the first compound contains 10 grams of sodium, 211 grams of potassium,

7 grams of lead, and 215 grams of zinc. The second sample contains 169 grams of zinc, 108 grams of lead, 88 grams of potassium, and 30 grams of sodium. The third sample contains 55 grams of lead, 254 grams of potassium, 56 grams of sodium, and 129 grams of zinc. The last sample contains 89 grams of sodium, 38 grams of lead, 64 grams of zinc, and 150 grams of potassium. Use these data to make a table.
Chemistry
1 answer:
Zarrin [17]3 years ago
6 0

Answer:

yea yea

Explanation:

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both sugar and phosphate molecules

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What are the evidences for suspecting the presence of waves?
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Well,

Conducting rods are good for detecting oscillating electric fields and conducting loops are good for detecting the presence of radio waves.  

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If 0.580 moles of a monoprotic weak acid (ka = 7.4 10-5 is titrated with naoh, what is the ph of the solution at the half-equiva
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3 years ago
How many grams of aluminum is produced when 82.4 grams of aluminum chloride
yKpoI14uk [10]

Answer:

16.6 g of Al are produced in the reaction of 82.4 g of AlCl₃

Explanation:

Let's see the decomposition reaction:

2AlCl₃ →  2Al  + 3Cl₂

2 moles of aluminum chloride decompose to 2 moles of solid Al and 3 moles of chlorine gas.

We determine the moles of salt:

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Ratio is 2:2. 2 moles of salt, can produce 2 moles of Al

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6 0
3 years ago
In a two-step synthesis, C6H11Br is converted into C6H12O. From the structure of the product, molecular formula of the starting
tamaranim1 [39]

Answer:

See explanation below

Explanation:

The question is incomplete. However in picture 1, you have the starting materials and the structure of the product, which you miss in this part.

Now, in picture 2, you have the starting reactant and the product, and the mechanism that is taking place here.

First, all what we have here is an acid  base reaction. In the first step, we are using the acid medium to convert the reactant into an alcohol. The bromine there, is not leaving the molecule yet, because it's neccesary for the next step. The starting reactant is an alkene, in that way, we can convert the reactant in the first step into a secondary alcohol. In other words, the first reaction is a alkene hydration.

In the second step, we use a strong base. You may say this is a strong nucleophile and will do a Sn2 reaction to form another alcohol there, but it's not the case, because, before any kind of reaction happens, the priority here is always the acid base, so the base will react with the acidic hydrogen. In this case, it will substract an hydrogen from the OH. When this happens, the lone pair will do an auto condensation here, and attacks the bromine in the molecule. In this way, the molecule will become a cyclomolecule, and that way it form the final product.

See picture 2, for mechanism

8 0
3 years ago
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