3 years ago

What is the surface area of this triangular prism? 6.5 ft 6 ft- 11 ft 5 ft

Mathematics

1 answer:

alexgriva [62]3 years ago

7 0

11 ft I guess not sure tho

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3 years ago

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In triangle △JKL, ∠JKL is right angle, and KM is an altitude. JL=25 and JM=5, find KM.

d1i1m1o1n [39]

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KM = 15

Step-by-step explanation:

From the diagram, ΔJKL and ΔJKM are similar to each other because they share the same angle J and they are both right angle triangle. Therefore they are similar by AA property.

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Since ΔJKL and ΔJKM are similar to each other, therefore:

$\frac{JK}{JL}=\frac{JM}{JK}\\ Substituting:\\\frac{JK}{30}=\frac{5}{JK}\\JK^2=150\\JK=\sqrt{150}\\ \\From\ hypotenuse:\\JK^2=JM^2+KM^2\\Substituting:\\(\sqrt{150} )^2=5^2+KM^2\\150=25+KM^2\\KM^2=150-25=125\\KM=\sqrt{125}\\ KM=15$

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