5 x 1 = 5
5 x 2 = 10
5 x 3 = 15
5 x 7 = 35
Answer:
131.87-23.24=108.63
Step-by-step explanation:
To solve this problem, let's line up the problem. To make it easier, we can start by ignoring the decimals.
13187
- 2324
______
10863
And then, since there were decimals in the first place, we have to add them back in.
10863→108.63
Answer:

Step-by-step explanation:
We want to find the inverse of
![y = \sqrt[3]{ \frac{x}{3} + 1}](https://tex.z-dn.net/?f=%20y%20%3D%20%5Csqrt%5B3%5D%7B%20%5Cfrac%7Bx%7D%7B3%7D%20%2B%201%7D%20)
We interchange x and y to get:
![x= \sqrt[3]{ \frac{y}{3} + 1}](https://tex.z-dn.net/?f=x%3D%20%5Csqrt%5B3%5D%7B%20%5Cfrac%7By%7D%7B3%7D%20%2B%201%7D%20)
We solve for y;

Multiply through by 3

Subtract 1 from both sides:

Therefore the inverse is

Answer:
y=1/2x+6
Step-by-step explanation:
Lines that are parallel will have the same slope, so the slope will remain 1/2. However, the y-intercepts can't be the same because then they will overlap each other instead. So we must solve for the missing y-intercept in this case:
y = 1/2x + b
4 = 1/2(-4) + b
4 = -2 + b
6 = b
b = 6
Since the y-intercept is b=6, then the equation of the line that passes through the point (-4,4) and is parallel to the line y=1/2x-4 is y=1/2x+6
9514 1404 393
Answer:
- zeros: t = 1, t = -1/2
- no: the domain of the function is t ≥ 0
- 8 feet
Step-by-step explanation:
The zeros are the values of t that make the factors zero.
1 -t = 0 ⇒ t = 1
8 +16t = 0 ⇒ t = -8/16 = -1/2
The equation is used to model height after the ball is thrown. We don't expect it to be a good model before the ball is thrown (t < 0), so the zero in that region is extraneous.
Only the positive zero is in the function's domain, so that is the only one that is meaningful.
__
When t = 0 (at the time the ball is thrown), the function value is ...
h(0) = (1 -0)(8 +0) = 8
The ball is thrown from a height of 8 feet.