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Hunter-Best [27]
3 years ago
9

Because cosmic distances are so vast, astronomers use light-years as their unit of distance. One light-year is defined as ______

_________________. The nearest star is a little more than ____ light-years away from us. When we see light from a galaxy 2 million light-years away, it has taken _______________ to reach us. Light from the Sun takes ___________ to reach us.
Physics
1 answer:
8090 [49]3 years ago
7 0

Answer:

Because cosmic disaster are so vast, astronomers use light-years as their unit of distance. One light-year is defined as <u>the distance a beam of light travels in one year</u>. The nearest star is a little more than <u>4.37 light-years</u> away from us. When we see light from a galaxy 2 million light-years away, it has taken<u> 2 million Earth years</u> to reach us. Light from the Sun takes <u>approximately 8.4269 minutes</u> to reach us

Explanation:

i) One light-year is defined as the distance a light beam travels in a time of one Earth year. One light year is equivalent to 6 × 10¹² miles or 9.7 × 10¹² km

ii) The distance to the nearest star =  4.37 light-years

iii) When a star located in a galaxy that is 2.3 million light years away is seen, it has taken 2.3 million light years to reach us

iv) The distance of the Sun to the Earth = 151.58 million kilometers

The speed of light, c = 299792.458 km/s

The time it will take light to reach us from the Sun, 't', is given as follows;

t = 151.58 × 10⁶ km/(299792.458 km/s) ≈ 8.4269 minutes.

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A wave's frequency is 2Hz and its wavelength is 4 m. What is the wave's speed?
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A turntable that spins at a constant 80.0 rpmrpm takes 3.50 ss to reach this angular speed after it is turned on. Find its angul
Veronika [31]

Answer:

The angular acceleration is <u>2.39 rad/s²</u>.

The number of degrees it rotates is <u>841.68 degrees</u>.

Explanation:

Given:

Initial angular speed (ω₀) = 0 rad/s

Final angular speed in rpm (N) = 80.0 rpm

Time taken (t) = 3.50 s

First, let us determine the final angular speed in radians per second.

We know that,

\omega=\frac{2\pi N}{60}\ rad/s

Plug in the values and find the final angular speed, 'ω'. This gives,

\omega=\frac{2\pi\times 80.0}{60}=8.38\ rad/s

Now, using equation of motion for rotational motion, we have:

\omega=\omega_0+\alpha t\\\\\alpha\to angular\ acceleration

Plug in the given values and solve for α. This gives,

8.38=0+\alpha \times 3.50\\\\\alpha=\frac{8.38}{3.50}=2.39\ rad/s^2

Therefore, the angular acceleration is 2.39 rad/s².

Now, again using rotational equation of motion relating angular displacement, we have:

\omega^2=\omega_0^2+2\alpha\theta\\\\\theta=\frac{\omega^2-\omega_0^2}{2\alpha }

Plug in the given values and solve for 'θ'. This gives,

\theta=\frac{(8.38)^2-0}{2\times 2.39}\\\\\theta=\frac{70.2244}{4.78}=14.69\ rad

Convert radians to degrees using the conversion factor. This gives,

π radians = 180°

So, 1 radian =( 180 ÷ π ) degrees

Therefore, 14.69\ rad=14.69\times (\frac{180}{\pi})=841.68^\circ

So, the number of degrees it rotates is 841.68 degrees.

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