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chubhunter [2.5K]
3 years ago
8

What nuclear process changes one element into another different element?

Physics
2 answers:
klio [65]3 years ago
6 0
The answer would option C
Semmy [17]3 years ago
4 0
The answer is nuclear transmutation
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Assume that in the Stern-Gerlach experiment for neutral silver atoms, the magnetic field has a magnitude of B = 0.21 T. (a) What
Marat540 [252]

Answer:

Explanation

Assume that in the Stern-Gerlach experiment for neutral silver atoms, the magnetic field has a magnitude of B = 0.21 T

A. To calculate the energy difference in the magnetic moment orientation

∆E = 2μB

For example, any electron's magnetic moment is measured to be 9.284764×10^−24 J/T

Then

μ = 9.284764 × 10^-24 J/T

∆E = 2μB

∆E = 2 × 9.284764 × 10^-24 × 0.21

∆E = 3.8996 × 10^-24 J

Then, to eV

1eV = 1.602 × 10^-19J

∆E = 3.8996 × 10^-24 J × 1eV / 1.602 × 10^-19J

∆E = 2.43 × 10^-5 eV

B. Frequency?

To determine the frequency of radiation hitch would induce the transition between the two states is,

∆E = hf

Where h is plank constant

h = 6.626 × 10-34 Js

Then, f = ∆E / h

f = 3.8996 × 10^-24 / 6.626 × 10^-34

f = 5.885 × 10^9 Hz

f ≈ 5.89 GHz

C. The wavelength of the radiation

From wave equation

v = fλ

In electromagnetic, we deal with speed of light, v = c

And the speed of light in vacuum is

c = 3 × 10^8 m/s

c = fλ

λ = c / f

λ = 3 × 10^8 / 5.885 × 10^9

λ = 0.051 m

λ = 5.1 cm

λ = 51 mm

D. It belongs to the microwave

From table

Micro waves ranges from

•Wavelength 10 to 0.01cm

Then we got λ = 5.1 cm, which is in the range.

•Frequency 3GHz to 3 Thz

Then, we got f ≈ 5.89 GHz, which is in the range

•Energy 10^-5 to 0.01 eV

We got ∆E = 2.43 × 10^-5 eV, which is in the range of the microwave

The value above is in microwave range

5 0
3 years ago
If there are 20 waves in a 5-second time frame, what is the frequency?
creativ13 [48]
Your answer would be 0.20 Hz
3 0
3 years ago
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An unusually high tide is called a _______ tide.
Monica [59]
 Proxigean Spring <span>Tide</span>
8 0
3 years ago
Whenever the net force on a moving object is zero its acceleration is
adell [148]

We only need to look at Newton's 2nd law of motion:

Net force = (mass) x (acceleration)

If the net force on an object is zero, then either its mass or its acceleration must be zero.  If it's called an "object", then its mass isn't zero, so its acceleration is zero.

5 0
3 years ago
Single Stage 0.0/3.0 points (graded) Consider a rocket carrying 100,000 kg of propellant, 10,000 kg of structure, and 5000 kg of
Nonamiya [84]

Answer: The Propellant fraction is 0.87.

The payload fraction is 0.04.

Δv = 8991.81 m/s

Explanation: To determine the fractions, first, calculate the total mass of the rocket:

m_{t} = m_{prop} + m_{str} + m_{pay}

m_{t} = 100,000 + 10,000 + 5,000

m_{t} = 115,000

The Propellant Fraction will be

m_{prop} = \frac{m_{prop}}{m_{t}}

m_{prop} = \frac{100,000}{115,000}

m_{prop} = 0.87

The Payload Fraction is:

m_{pay} = \frac{m_{pay}}{m_{t}}

m_{pay} = \frac{5,000}{115,000}

m_{pay} = 0.04

The value of Δv is calculated by the formula:

Δv = -V_{e}. ln(\frac{m_{final}}{m_{initial}} )

The exhaust velocity (V_{e}) is:

V_{e} = g_{0}.Isp

V_{e} = 9.81*450

V_{e} = 4414.5

m_{final} is the total mass after the rocket consume all the propellant and m_{initial} is the total mass before the action.

Δv = -V_{e}. ln(\frac{m_{final}}{m_{initial}} )

Δv = -4414.5.ln(\frac{15,000}{115,000} )

Δv = - 4414.5.ln(0.13)

Δv = 8991.81

Δv will be 8991.81 m/s.

7 0
3 years ago
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