From that list, the only unit of mass is the "gram".
But that isn't the SI base unit of mass.
The base unit is the kilogram.
Since each light year is approximately 9 trillion kilometres, 4.80 light years is 43.2 trillion kilometres, or 43,200,000,000,000,000 metres
Answer:
The amount of kilograms of ice at -20.0°C that must be dropped into the water to make the final temperature of the system 40.0°C = 0.0674 kg
Explanation:
Heat gained by ice in taking the total temperature to 40°C = Heat lost by the water
Total Heat gained by ice = Heat used by ice to move from -20°C to 0°C + Heat used to melt at 0°C + Heat used to reach 40°C from 0°C
To do this, we require the specific heat capacity of ice, latent heat of ice and the specific heat capacity of water. All will be obtained from literature.
Specific heat capacity of ice = Cᵢ = 2108 J/kg.°C
Latent heat of ice = L = 334000 J/kg
Specific heat capacity of water = C = 4186 J/kg.°C
Heat gained by ice in taking the total temperature to 40°C = mCᵢ ΔT + mL + mC ΔT = m(2108)(0 - (-20)) + m(334000) + m(4186)(40 - 0) = 42160m + 334000m + 167440m = 543600 m
Heat lost by water = mC ΔT = 0.25 (4186)(75 - 40) = 36627.5 J
543600 m = 36627.5
m = 0.0674 kg = 67.4 g of ice.
Answer:
The time it takes the stone to reach the bottom of the cliff is approximately 4.293 s
Explanation:
The given parameters are;
The height of the cliff, h = 90.4 m
The direction in which the stone is thrown = Horizontally
The speed of the stone in the horizontal direction = 10 m/s
The time, t, it takes the stone to reach the bottom of the cliff is given by the equation for free fall as follows;
h = 1/2 × g × t²
Where;
g = The acceleration due to gravity = 9.81 m/s²
Substituting the values gives;
90.4 = 1/2 × 9.81 × t²
t² = 90.4/(1/2 × 9.81) ≈ 18.43 s²
t = √18.43 ≈ 4.293 s
The time it takes the stone to reach the bottom of the cliff is t ≈ 4.293 s.