PV=nRT
(P)(86.5)=(41.5)(.08206)(300.15)
(P)(86.5)=(1022.157824)
P=11.81685345 atm
No. If time is the horizontal axis and distance is the vertical axis, then
it is not possible for a distance-vs-time graph to be a vertical line.
A vertical line would mean:
-- the object was at all distances at the same time,
-- it moved from any location to any other location in no time, and
-- it moved with infinite speed.
Even light doesn't do that. A distance-vs-time graph for light is
not a vertical line. It's a slanted line with slope of (3 x 10⁸) m/s.
Purty durn steep, but not vertical.
Answer:
D = 14.31 m
Explanation:
It is given that,
Displacement due east is 12 m
Displacement due north is 5 m
Displacement in vertically upward direction is 6 m
We need to find the magnitude of the sum of these displacements. We know that, vertically upward, east and north are mutually perpendicular direction. So, the resultant is given by :
So, the magnitude of the sum of these displacements is 14.31 m.
The second world war, and its war weapons, such as the v-2 rockets, had a great impact on the world until today, to answer this question we need that...
<h3>
V-2 factory </h3>
On April 11, 1945, US troops took the town of Bleicherode, in the Kohnstein region, where the V-2 factory was located. From there about 100 complete V-2s and thousands of parts and equipment were "captured" as war loot and transferred to the United States, where they formed the basis for practical studies of the missile defense program.
With this information, we can say that because it was a base discovered by US troops, none of the alternatives is correct, as it was not the Soviets who discovered it, and that the base was also located in the central part of Germany.
<u>The </u><u>v-2 factory</u><u> was located in </u><u>Kohnstein, central germany,</u><u> by this claim, </u><u>none of the alternatives is correct.</u>
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