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2 years ago

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Average velocity is different than average speed because calculating average velocity involves

1 answer:

zheka24 [161]2 years ago

8 0

The correct answer is displacement.

Average velocity differs from average speed because displacement is used to calculate average velocity.

What is displacement?

Being a vector, displacement has both magnitude and direction. In one-dimensional motion, the direction should be stated with a plus or minus sign to ensure sure the direction is right. It always occurs in a straight line between two sites. Although it is not a vector variable and lacks a direction sign, the word "distance traveled" is also used to refer to the length of the path that was taken to get from one place to another. The distance traveled is not always equal in both magnitude and direction; on occasion, it may exceed the magnitude of the displacement between the sites.

To learn more about displacement refer the link:

brainly.com/question/11934397

#SPJ9

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4 years ago

The Jamaican bobsled team hit the brakes on their sled so that it decelerates at a uniform rate of 0.43 m/s^2. How long does it

topjm [15]

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Explanation: Hope this helps

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3 years ago

PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!!

den301095 [7]

A: 0.7 -0.8 and 0hrs
B: 0.2 - 0.4 and 1.0 -1.1 hrs
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3 years ago

Read 2 more answers

A person standing 1.20 m from a portable speaker hears its sound at an intensity of 5.50 ✕ 10−3 W/m2. HINT (a) Find the correspo

iris [78.8K]

Answer:

PART A)

L = 97.4 dB

PART B)

$I = 6.11 \times 10^{-6} W/m^2$

PART C)

L = 67.9 dB

Explanation:

PART A)

level of sound is given as

$L = 10 Log\frac{I}{I_o}$

now we have

$L = 10 Log\frac{5.50\times 10^{-3}}{10^{-12}}$

$L = 97.4 dB$

PART B)

Since source is a spherical source

so here the intensity of sound is inversely depends on the square of the distance from the source

$\frac{I_2}{I_1} = \frac{r_1^2}{r_2^2}$

$\frac{I_2}{5.50 \times 10^-3} = \frac{1.20^2}{36^2}$

$I_2 = 6.11 \times 10^{-6} W/m^2$

PART C)

level of sound is given as

$L = 10 Log\frac{I}{I_o}$

now we have

$L = 10 Log\frac{6.11\times 10^{-6}}{10^{-12}}$

$L = 67.9 dB$

3 0

3 years ago

Gravity accelerates any object falling at 9.8 m/s2. What is the force that will be applied to the ground if an 88 kg box falls f

saw5 [17]

Answer:

The force is of the weight <u>862,4 Newtons.</u>

<u></u>

Explanation:

We have the formula:

w = m * g

Data:

w = weight = ¿?

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Replacing according formula:

w = 88 kg * 9,8 m/s

Resolving:

w = 862,4 N

6 0

3 years ago