The setup boxes in the synthetic division are (b)
<h3>How to determine the setup boxes?</h3>
The dividend is given as:
x^3 + 4x^2 + x - 6
The divisor is given as:
x - 2
Set the divisor to 0
x - 2 = 0
Solve for x
x = 2
Remove the variables in the dividend
1 + 4 + 1 - 6
Remove the arithmetic signs
1 4 1 - 6
So, the setup is:
2 | 1 4 1 - 6
Hence, the setup boxes are (b)
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The parts (a) to (c) can be completed using the equtaion y ⇔ Δ ∈ ∞, ㏒Δ ∀ x∈√a, a∈R.
Answer:
The smaller number is 11.
Step-by-step explanation:
11 + 13 = 24
11 x 13 = 143
Hope this helps!
I got 2.17 but I'm not sure that's right.
