1 liter = 1000 cm^3
20cm * 20cm * 20cm = 8000 cm^3
8000/1000 = 8 liters
Since 1ml of water = 1 cm^3 = 1 grams
8 liters = 8000 grams = 8 kilograms
You need to consider the following:
Me (mass of Earth) = 5.98 x 10^24 kg
<span>Ms (mass of Sun) = 1.99 x 10^30 kg </span>
<span>G = 6.67 x 10^-11 N </span>
<span>
Formula:
F = G * M1M2/r^2
</span><span>The ratio FT/F = 4.02x10^-4 / 14.8
= 2.72x10^-5
</span><span>
Since,
1/2.72x10^-5 = 36800
The fraction ratio is 1/36800
</span>= <span>9.56x10^17 N</span>
Answer:
The ratio of the orbital time periods of A and B is 
Solution:
As per the question:
The orbit of the two satellites is circular
Also,
Orbital speed of A is 2 times the orbital speed of B
(1)
Now, we know that the orbital speed of a satellite for circular orbits is given by:

where
R = Radius of the orbit
Now,
For satellite A:

Using eqn (1):
(2)
For satellite B:
(3)
Now, comparing eqn (2) and eqn (3):

Answer:
The average current that this cell phone draws when turned on is 0.451 A.
Explanation:
Given;
voltage of the phone, V = 3.7 V
electrical energy of the phone battery, E = 3.15 x 10⁴ J
duration of battery energy, t = 5.25 h
The power the cell phone draws when turned on, is the rate of energy consumption, and this is calculated as follows;

where;
P is power in watts
E is energy in Joules
t is time in seconds

The average current that this cell phone draws when turned on:
P = IV

Therefore, the average current that this cell phone draws when turned on is 0.451 A.
I would say B but I’m not 100%