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sweet-ann [11.9K]
3 years ago
11

Choose the element that has a smaller atomic radius :scandium or selenium

Physics
1 answer:
nikdorinn [45]3 years ago
4 0
Choose the element that has a smaller atomic radius :scandium
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What volume In liters is a cube 20cm on a side? If the cube is filled with water what is the mass of the water?
frez [133]
1 liter = 1000 cm^3
20cm * 20cm * 20cm = 8000 cm^3
8000/1000 = 8 liters

Since 1ml of water = 1 cm^3 = 1 grams
8 liters = 8000 grams = 8 kilograms
7 0
3 years ago
Calculate the total force on the Earth due to Venus, Jupiter, and Saturn, assuming all four planets are in a line. The masses ar
Furkat [3]
You need to consider the following:
Me (mass of Earth) = 5.98 x 10^24 kg 
<span>Ms (mass of Sun) = 1.99 x 10^30 kg </span>
<span>G = 6.67 x 10^-11 N </span>
<span>
Formula:
 F = G * M1M2/r^2 
</span><span>The ratio FT/F = 4.02x10^-4 / 14.8
 = 2.72x10^-5 
</span><span>
Since,
1/2.72x10^-5 = 36800
The fraction ratio is  1/36800
</span>= <span>9.56x10^17 N</span>
3 0
3 years ago
Read 2 more answers
Two satellites, A and B are in different circular orbits
jek_recluse [69]

Answer:

The ratio of the orbital time periods of A and B is \frac{1}{2}

Solution:

As per the question:

The orbit of the two satellites is circular

Also,

Orbital speed of A is 2 times the orbital speed of B

v_{oA} = 2v_{oB}        (1)

Now, we know that the orbital speed of a satellite for circular orbits is given by:

v_{o} = \farc{2\piR}{T}

where

R = Radius of the orbit

Now,

For satellite A:

v_{oA} = \farc{2\piR}{T_{a}}

Using eqn (1):

2v_{oB} = \farc{2\piR}{T_{a}}           (2)

For satellite B:

v_{oB} = \farc{2\piR}{T_{b}}              (3)

Now, comparing eqn (2) and eqn (3):

\frac{T_{a}}{T_{b}} = \farc{1}{2}

6 0
3 years ago
The battery for a certain cell phone is rated at 3.70 V. According to the manufacturer it can produce math]3.15 \times 10^{4} J[
AysviL [449]

Answer:

The average current that this cell phone draws when turned on is 0.451 A.

Explanation:

Given;

voltage of the phone, V = 3.7 V

electrical energy of the phone battery, E = 3.15 x 10⁴ J

duration of battery energy, t = 5.25 h

The power the cell phone draws when turned on, is the rate of energy consumption, and this is calculated as follows;

P = \frac{E}{t}

where;

P is power in watts

E is energy in Joules

t is time in seconds

P = \frac{3.15*10^4}{5.25*3600s} = 1.667 \ W

The average current that this cell phone draws when turned on:

P = IV

I = \frac{P}{V} =\frac{1.667}{3.7} = 0.451 \ A

Therefore, the average current that this cell phone draws when turned on is 0.451 A.

5 0
3 years ago
Anyone want to help a brother out
s344n2d4d5 [400]
I would say B but I’m not 100%
5 0
3 years ago
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