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Lelu [443]
4 years ago
7

A slug traveling at 3 mm/h, East decided to race the slug next to him increasing his velocity to 5 mm/h, East in one hour. What

was the slug's acceleration?
Physics
1 answer:
N76 [4]4 years ago
7 0

The Acceleration of  slug  would be 2 mm/hr²

<u> Step by step Explanation:</u>

Given of the solution

Initial velocity of the slug,(we can represent as v_{i})  v_{i}= 3 mm/hr

Final velocity of the slug,(we can represent as v_{f} ) v_{f}= 5 mm/hr

Time, t = 1 hr

Acceleration, a = ?

We know,

a = \frac{(5-3)}{1} \\\\a = 2 mm/hr^2

Therefore, The Acceleration of  slug would be 2 mm/hr²

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Answer:

12N

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3 years ago
The speed of a wave in a medium is effected by____,____, and____
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As per as my knowledge

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7 0
3 years ago
You set your stationary bike on a high 80-N friction-like resistive force and cycle for 30 min at a speed of 8.0 m/s . Your body
stellarik [79]

A) The change in internal chemical energy is 1.15\cdot 10^7 J

B) The time needed is 1 minute

Explanation:

First of all, we start by calculating the power output of you and the bike, given by:

P=Fv

where

F = 80 N is the force that must be applied in order to overcome friction and travel at constant speed

v = 8.0 m/s is the velocity

Substituting,

P=(80)(8.0)=640 W

The energy output is related to the power by the equation

P=\frac{E}{t}

where:

P = 640 W is the power output

E is the energy output

t = 30 min \cdot 60 = 1800 s is the time elapsed

Solving for E,

E=Pt=(640)(1800)=1.15\cdot 10^6 J

Since the body is 10% efficient at converting chemical energy into mechanical work (which is the output energy), this means that the change in internal chemical energy is given by

\Delta E = \frac{E}{0.10}=\frac{1.15\cdot 10^6}{0.10}=1.15\cdot 10^7 J

B)

From the previous part, we found that in a time of

t = 30 min

the amount of internal chemical energy converted is

E=1.15\cdot 10^7 J

Here we want to find the time t' needed to convert an amount of chemical energy of

E'=3.8\cdot 10^5 J

So we can setup the following proportion:

\frac{t}{E}=\frac{t'}{E'}

And solving for t',

t'=\frac{E't}{E}=\frac{(3.8\cdot 10^5)(30)}{1.15\cdot 10^7}=1 min

Learn more about power and energy:

brainly.com/question/7956557

#LearnwithBrainly

3 0
3 years ago
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Answer:

Wave model

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