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DochEvi [55]
4 years ago
15

A delivery truck is transporting boxes of two sizes: large and small. The combined weight of a large box and a small box is 85 p

ounds. The truck is transporting 50 large boxes and 55 small boxes. If the truck is carrying a total of 4375 pounds in boxes, how much does each type of box weigh?
Large box: - pounds
Small box: - pounds
Mathematics
1 answer:
MrRa [10]4 years ago
6 0

Let small box = X and large box = y

Set up two equations:

X + Y = 85 pounds.

Rewrite as X = 85 - y

and:

55x + 50Y = 4375 pounds.

Replace x:

55(85 - y) + 50y = 4375

Use distributive property:

4675 - 55y + 50y = 4375

Combine like terms:

4675 - 5y = 4375

Subtract 4675 from both sides:

-5y = -300

Divide both sides by -5:

y = 60

This is the weight of the large box.

The small box would weigh 85 - 60 = 25 pounds.

Large box = 60 pounds.

Small box = 25 pounds.

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In an insect colony there are 270 insects after 9 days. If there were initially 80 insects how long will it take the population
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Answer:

The time it will take the population to grow to 800 insects is 17 days.

Step-by-step explanation:

The growth function of the insects is exponential.

The exponential growth function is:

y=a(1+r)^{t}

Here,

<em>y</em> = final value

<em>a</em> = initial value

<em>r</em> = growth rate

<em>t</em> = time taken

It is provided that there were 270 insects after 9 days and initially there were 80 insects.

Compute the value of <em>r</em> as follows:

y=a(1+r)^{t}\\\\270=80(1+r)^{9}\\\\3.375=(1+r)^{9}\\\\\ln(3.375)=9\cdot \ln(1+r)\\\\0.135155=\ln(1+r)\\\\1+r=1.14471\\\\r=0.145

Now, compute the time it will take the population to grow to 800 insects as follows:

800=80(1+0.145)^{t}\\\\10=(1.145)^{t}\\\\\ln(10)=t\cdot \ln(1.145)\\\\t=17.00522\\\\t\approx 17

Thus, the time it will take the population to grow to 800 insects is 17 days.

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