Water has a K, value of 1x 10-13 1x 10-10 1x 10-15 1x 10-14
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Answer:
10.86
Explanation:
Given that:
Concentration = 0.0288 M
Consider the ICE take for the dissociation of ammonia as:
NH₃ + H₂O ⇄ NH₄⁺ + OH⁻
At t=0 0.0288 - -
At t =equilibrium (0.0288-x) x x
The expression for dissociation constant of ammonia is:
x is very small, so (0.0288 - x) ≅ 0.0288
Solving for x, we get:
x = 7.2×10⁻⁴ M
pOH = -log[OH⁻] = -log(7.2×10⁻⁴) = 3.14
Also,
pH + pOH = 14
So, pH = 10.86