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Troyanec [42]
4 years ago
8

How many grams of neon gas should be placed into a 10.0 L container in order for it to meet STP conditions?

Chemistry
1 answer:
bearhunter [10]4 years ago
6 0
9.0 grams because the atomic mass of 1 mole of Neon STP(22.4L) is 20.17 and cross multiply 10.0g(given) by the 20.17, and divide by 22.4L to get 9.00 grams of Neon to match 10L container at STP
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In the experiment "Preparation and Standardization of a Sodium Hydroxide Solution", why was the burette rinsed with NaOH before
FromTheMoon [43]

Answer: The correct option is ALL OF THE ABOVE.

Explanation:

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During titration, the following precautions should be followed to avoid errors and maintain standardisation in the experiment.

--> Any air bubble in the burette and pipette must be removed during measurement

--> the burette tap should be tightened to avoid leakage.

--> Remove the funnel from the burette before taking any reading to avoid errors in reading the volume.

--> use the base solution such as Sodium Hydroxide Solution to rinse the burette after washing with soap and tap water:

• to remove any air bubble and fill it's tip

• to remove any residual liquid from the water and soap solution which may interfere with the results of the experiment.

• to check if the burette is in good condition.

Therefore all of the above options to the question are correct.

3 0
3 years ago
Which material is the least likely to be recognized as a mixture by looking at it under a microscope?
adelina 88 [10]
I don't know what the options were but a material that is very likely going to be challenging to recognize under a microscope as a mixture is a homogeneous mixture. A homogenous mixture is uniform and thus hard to recognize as a mixture. An example is water!
7 0
3 years ago
Read 2 more answers
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5 0
4 years ago
If two substances travel up the chromatography paper this implies that
Colt1911 [192]

Answer:

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Explanation:

6 0
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What compound is formed when 2,2-dimethyloxirane (2-methyl-1,2-epoxypropane) is treated with ethanol containing sulfuric acid
vladimir1956 [14]

Answer:

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Explanation:

On this reaction, we have an "<u>epoxide"</u> (2-methyl-1,2-epoxypropane). Additionally, we have <u>acid medium</u> (due to the sulfuric acid H_2SO_4). The acid medium will produce the <u>hydronium ion</u> (H^+). This ion would be attacked by the oxygen of the epoxide. Then a <u>carbocation</u> would be produced, in this case, the most stable carbocation is the <u>tertiary one</u>. Then an <u>ethanol</u> molecule acts as a nucleophile and will attack the carbocation. Finally, a <u>deprotonation </u>step takes place to produce <u>2-ethoxy-2-methylpropan-1-ol</u>.

See figure 1

I hope it helps!

3 0
3 years ago
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