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mrs_skeptik [129]
2 years ago
8

A 50.0 mL sample of 12.0 M HCl is diluted to 200 mL. What is true about the diluted solution?

Chemistry
1 answer:
kobusy [5.1K]2 years ago
7 0

The concentration of the solution reduces and the number of moles of solute isn't affected.

Data;

  • V1 = 50mL
  • C1 = 12.0M
  • V2 = 200mL
  • C2 = ?
<h3>Facts about the diluted solution</h3>

1. When the solution is diluted, the concentration changes and this time, the concentration reduces.

Using dilution formula

c_1 v_1 = c_2 v_2\\12 * 50 = c_2 * 200\\c_2 = \frac{600}{200} \\c_2 = 3M

The concentration of the solution reduces.

2. The number of moles remains the same.

When a solution is diluted, the number of moles remains the same because there's no change in the mass of the solute.

Learn more on concentration of a solution here;

brainly.com/question/2201903

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b) Si los ácidos nitroso y fluorhídrico están descritos como electrolitos débiles, ¿significa que en la disolución hay moléculas
viva [34]

Los electrolitos son sustancias que se disocian en agua para dar iones.

Generalmente en química, podemos clasificar sustancias como

  • Electrolitos
  • No electrolitos

Los electrolitos pueden disociarse en solución para producir iones, pero un no electrolito no puede hacer eso.

Entre los electrolitos hay dos clases;

  • Electrolitos fuertes
  • Electrolitos débiles

Los electrolitos fuertes se disocian completamente en solución, mientras que los electrolitos débiles no se disocian completamente en solución.

El hecho de que los electrolitos débiles no se disocien por completo significa que algunas moléculas de la sustancia no se disocian.

Por lo tanto, si los ácidos nitroso y fluorhídrico se describen como electrolitos débiles, esto significa que hay moléculas en la solución que no están disociadas.

Lea más: brainly.com/question/14566383

5 0
2 years ago
Which of the following describes the relationship correctly?
galben [10]
A. Air expands, becomes less dense and rises when the temperature is high due to the increased kinetic energy. This causes the air molecules to move around much more so they are further apart.
8 0
3 years ago
Read 2 more answers
An alkane with the formula C6H14 can be prepared by hydrogenation of either of two precursor alkenes having the formula C6H12.
ankoles [38]
Two precursor alkenes

    H₃C  CH₃
         I   I
H₂C=C-CH-CH₃    2,3-dimethyl-1-butene

   H₃C      CH₃
        I       I
H₃C-CH=CH-CH₃    2,3-dimethyl-2-butene


alkane

   H₃C     CH₃
        I      I
H₃C-CH-CH-CH₃    2,3-dimethylbutane

    H₃C  CH₃                        H₃C     CH₃
         I   I                                   I      I
H₂C=C-CH-CH₃  + H₂ → H₃C-CH-CH-CH₃ 
  
    H₃C   CH₃                       H₃C     CH₃
        I    I                                   I      I
H₂C-C=CH-CH₃  + H₂ → H₃C-CH-CH-CH₃ 

6 0
3 years ago
Read 2 more answers
The molecular weight of NaCl is 58.44 grams/moles. How many grams of NaCl are found in a beaket with 100 ml of a 0.0050 M soluti
Viktor [21]

Answer:

The mass of NaCl is 0.029 grams

Explanation:

Step 1: Data given

Molecular weight of NaCl = 58.44 g/mol

Volume of solution = 100 mL = 0.100 L

Molarity = 0.0050 M

Step 2: Calculate moles NaCl

Moles NaCl = molarity * volume

Moles NaCl = 0.0050 M * 0.100 L

Moles NaCl = 0.00050 moles

Step 3: Calculate mass NaCl

Mass NaCl = moles NaCl * molar mass NaCl

Mass NaCl = 0.00050 moles * 58.44 g/mol

Mass NaCl = 0.029 grams

The mass of NaCl is 0.029 grams

4 0
3 years ago
I will give brainliest if done well.
topjm [15]

Answer:

8.37g

Explanation:

Step 1 :

The balanced equation for the reaction. This is given below:

N2 + 2O2 —> 2NO2

Step 2:

Data obtained from the question.

Volume (V) of N2 = 2L

Pressure (P) = 840mmHg

Temperature (T) = 24°C

Number of mole (n) of N2 =?

Step 3:

Conversion to appropriate unit.

For pressure:

760mmHg = 1atm

840mmHg = 840/760 = 1.11 atm

For Temperature:

T(K) = T(°C) + 273

T(°C) = 24°C

T(K) = 24°C + 273

T(K) = 297K

Step 4:

Determination of the number of mole N2.

The number of mole of N2 can be obtained by using the ideal gas equation as follow:

Volume (V) of N2 = 2L

Pressure (P) = 1.11 atm

Temperature (T) = 297K

Number of mole (n) of N2 =?

Gas constant (R) = 0.082atm.L/Kmol

PV = nRT

Divide both side by RT

n = PV / RT

n = 1.11 x 2 / 0.082 x 297

n = 0.091 mole

Therefore, the number of mole of N2 that reacted is 0.091 mole

Step 5:

Determination of the mass of NO2 produced from the reaction. This is illustrated below:

N2 + 2O2 —> 2NO2

From the balanced equation above,

1 mole of N2 produced 2 moles of NO2.

Therefore, 0.091 mole of N2 will produce = 0.091 x 2 = 0.182 mole of NO2.

Finally, we will convert 0.182 mole of NO2 to gram as shown below:

Number of mole NO2 = 0.182 mole

Molar mass of NO2 = 14 + (16x2) = 46g/mol

Mass = number of mole x molar mass

Mass of NO2 = 0.182 x 46

Mass of NO2 = 8.37g

7 0
3 years ago
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