Question

Helppp please I’m have no time quick please

Answer 1

Answer:

I = 1.09 A

Explanation:

Here, 5 ohm and 12 ohm resistor are connected in parallel. Using the parallel combination of resistors as follows :

$\dfrac{1}{R}=\dfrac{1}{R_1}+\dfrac{1}{R_2}\\\\\dfrac{1}{R}=\dfrac{1}{5}+\dfrac{1}{12}\\\\ R=3.52\ \Omega$

Now R and 2 ohm resistors are in series. Let the equivalent be $R_{eq}$. So,

$R_{eq}=3.52+2\\\\=5.52\ \Omega$

Let I be the current. Using Ohm's law,

V = IR

$I=\dfrac{V}{R_{eq}}\\\\I=\dfrac{6}{5.52}\\\\I=1.086\ A$

or

I = 1.09 A

So, the correct option is (c).