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sattari [20]
3 years ago
12

15 and 16 pls thank you ASAP ASAP

Mathematics
2 answers:
Delicious77 [7]3 years ago
5 0
Number 16 is D & 15 is D because in number 16 8y can’t equal X but 8 can be in the X&Y’s place. As for number 15 the correct equation is 2y=0-4. Add to 2y and the equation is left with 2y=-4 divide that and you get a positive 2. Pls make my answer the Brainliest, I would rlly appreciate it...Please and Thank You!
Digiron [165]3 years ago
4 0

Answer:

Number 16 is D & 15 is D

Step-by-step explanation:

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Answer:

Q1:

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Q2:

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Q3:

\sqrt{108yz}+3\sqrt{98yz}+2\sqrt{75yz}

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6\sqrt{3}\sqrt{yz}+21\sqrt{2}\sqrt{yz}+10\sqrt{3}\sqrt{yz}

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Q4:

\sqrt{15n^2}\sqrt{10n^3}

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\sqrt{15}n\sqrt{10}\sqrt{n^2}\sqrt{n}

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\sqrt{5}\sqrt{3}\sqrt{5}\sqrt{2}n^2\sqrt{n}

5\sqrt{3}\sqrt{2}n^2\sqrt{n}

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Q5:

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\frac{\sqrt{3}xy\sqrt{y}}{4\sqrt{5}y\sqrt{x}\sqrt{y}}

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\frac{\sqrt{3}y\sqrt{x}\sqrt{y}}{4\sqrt{5}y\sqrt{y}}

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\frac{\sqrt{3}\sqrt{x}\sqrt{y}}{4\sqrt{5}\sqrt{y}}

Cancel off \sqrt{y} :

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Multiply \sqrt{5} on the numerator and denominator:

\frac{\sqrt{3}\sqrt{x}\sqrt{5}}{4\sqrt{5}\sqrt{5}}

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Answer:

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