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Natasha2012 [34]
3 years ago
15

Tom has a mass of 50,000 g and runs up a flight of stairs 4 m high in 12.5 seconds.

Physics
1 answer:
Leya [2.2K]3 years ago
5 0

Answer:

160 watts.

Explanation:

Remark

Power = Work / Time

Work = F * d

Note: Since he is running up stairs he is doing work against gravity.

Givens

  • m = 50000 g   kg / 1000 grms
  • m = 50000 / 1000 = 50 kg
  • h = 4 m
  • time = 12.5 seconds
  • g = 10 m/s^2

Formula

  • P = W * d/t
  • W = m*g *d / t

Solution

  • P = 50kg * 10 m/s^2 * 4 m / 12.5
  • <em><u>P = 160 watts. </u></em>

<em><u></u></em>

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Answer:

156.8 Watts

Explanation:

From the question given above, the following data were obtained:

Mass (m) = 10 kg

Height (h) = 8 m

Time (t) = 5 s

Power (P) =?

Next, we shall determine the energy used by the motor to raise the block. This can be obtained as follow:

Mass (m) = 10 kg

Height (h) = 8 m

Acceleration due to gravity (g) = 9.8 m/s²

Energy (E) =?

E = mgh

E = 10 × 9. 8 × 8

E = 784 J

Finally, we shall determine the power output of the motor. This can be obtained as illustrated below:

Time (t) = 5 s

Energy (E) = 784 J

Power (P) =?

P = E/t

P = 784 / 5

P = 156.8 Watts

Therefore, the power output of the motor is 156.8 Watts

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3 years ago
A skydiver jumps from an airplane and falls freely for 5 seconds. If the sky diver's velocity increases by 49 m/s during that ti
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Acceleration  =  (change in speed)  /  (time for the change)

                       =      (49 m/s)   /   (5 seconds)

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N LC circuit has an oscillation frequency of 105 Hz. If C = 0.1 F , then L must be about:
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Answer:

L = 22.97 H

Explanation:

Given that,

Capacitance, C=0.1\ \mu F=0.1\times 10^{-6}\ F

Oscillation frequency, f = 0.5 Hz

The frequency of an AC circuit is given by :

f=\dfrac{1}{2\pi \sqrt{LC} }

Where

L is impedance

f^2=\dfrac{1}{4\pi ^2LC}\\\\L=\dfrac{1}{4\pi ^2 f^2 C}\\\\\text{Putting all the values}\\\\L=\dfrac{1}{4\pi^2 \times (105)^2\times 0.1\times 10^{-6}}\\\\L=22.97\ H

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7 0
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In a heat engine if 1000 j of heat enters the system the piston does 500 j of work, what is the final internal energy of the sys
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Answer : The final energy of the system if the initial energy was 2000 J is, 3500 J

Solution :

(1) The equation used is,

\Delta U=q+w\\\\U_{final}-U_{initial}=q+w

where,

U_{final} = final internal energy

U_{initial} = initial internal energy

q = heat energy

w = work done

(2) The known variables are, q, w and U_{initial}

initial internal energy = U_{initial} = 2000 J

heat energy = q = 1000 J

work done = w = 500 J

(3) Now plug the numbers into the equation, we get

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(4) By solving the terms, we get

U_{final}-(2000J)=(1000J)+(500J)

U_{final}-(2000J)=1500J

U_{final}=2000J+1500J

U_{final}=3500J

(5) Therefore, the final energy of the system if the initial energy was 2000 J is, 3500 J

5 0
3 years ago
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