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postnew [5]
3 years ago
11

How many miles is the moon from the earth

Physics
1 answer:
Usimov [2.4K]3 years ago
3 0
It is approximately 238,900 miles away from Earth.
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A penny is placed on a rotating turntable. where on the turntable does the penny require the largest centripetal force to remain
Mama L [17]

m = mass of the penny

r = distance of the penny from the center of the turntable or axis of rotation

w = angular speed of rotation of turntable

F = centripetal force experienced by the penny

centripetal force "F" experienced by the penny of "m" at distance "r" from axis of rotation is given as

F = m r w²

in the above equation , mass of penny "m"  and angular speed "w" of the turntable is same at all places. hence the centripetal force directly depends on the radius .

hence greater the distance from center , greater will be the centripetal force to remain in place.  

So at the edge of the turntable , the penny experiences largest centripetal force to remain in place.

4 0
3 years ago
In a liquid with a density of 1400 kg/m3 , longitudinal waves with a frequency of 370 Hz are found to have a wavelength of 8.40
VARVARA [1.3K]

Answer:

Bulk modulus = 1.35 × 10^{10} Pa

Explanation:

given data

density = 1400 kg/m³

frequency = 370 Hz

wavelength = 8.40 m

solution

we get here bulk modulus of the liquid that is

we know Bulk Modulus = v^2*\rho   ...............

here \rho is density i.e 1400 kg/m³

and v is =  frequency × wavelength

v = 370 × 8.40 = 3108 m/s

so here bulk modulus will be as

Bulk modulus = 3108² × 1400

Bulk modulus = 1.35 × 10^{10} Pa

3 0
3 years ago
The gravitational strength at the poles is greater than the gravitational strength at the equator. What will happen to an object
geniusboy [140]

Answer:

C

Explanation:

Because this same question was on my test last week and I got it correct

3 0
2 years ago
Question 10 of 30
Yuliya22 [10]

Answer:

Technology, the application of scientific knowledge to the practical aims of human life or, as it is sometimes phrased, to the change and manipulation of the human environment.

Explanation:

3 0
2 years ago
An automobile of mass 1.46 cross times to the power of blank 10 cubed kg rounds a curve of radius 25.0 m with a velocity of 15.0
Vsevolod [243]

The centripetal force exerted on the automobile while rounding the curve is 1.31\times10^4 N

<u>Explanation:</u>

given that

Mass\ of\ the\ automobile\ m  =1.46\times 10^3 kg\\radius\ of\ the\ curve\ r =25 m\\velocity\ of\ the\ automobile\ v=15m/s\\

Objects moving around a circular track will experience centripetal force towards the center of the circular track.

centripetal\ force=mv^2/r\\=1.46\times10^3\times15^2/25\\=1.46\times 10^3\times 225/15\\=1.31\times 10^4 N

4 0
3 years ago
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