Answer:
- 5/13
Step-by-step explanation:
tans = 5/12 = height/base
Using Pythagoras, hypotenuse = √12² + 5² = 13
Therefore coss had to be 12/13
But since cos s < 0, cos s = - 12/13
Thus,
tanA = sinA/cosA
tanA cosA = sinA
(5/12)(- 12/13) = sinA
- 5/13 = sinA
2.70g = c
you have 2 gallons so it would be 2.70(2)=5.40
gallons - g
cost - c
Since a calculator is involved in finding the answer, it makes sense to me to use a calculator capable of adding vectors.
The airplane's ground speed is 158 mph, and its heading is 205.3°.
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A diagram can be helpful. You have enough information to determine two sides of a triangle and the angle between them. This makes using the Law of Cosines feasible for determining the resultant (r) of adding the two vectors.
.. r^2 = 165^2 +15^2 -2*165*15*cos(60°) = 24975
.. r = √24975 ≈ 158.03
Then the angle β between the plane's heading and its actual direction can be found from the Law of Sines
.. β = arcsin(15/158.03*sin(60°)) = 4.7°
Thus the actual direction of the airplane is 210° -4.7° = 205.3°.
The ground speed and course of the plane are 158 mph @ 205.3°.
Nope this helps :)
I have attached a filled in photo...
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Answer:
27
Step-by-step explanation: