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DENIUS [597]
3 years ago
6

Firefighters need to use a 60-foot ladder to save a child. She is 50 feet above street

Mathematics
1 answer:
mr_godi [17]3 years ago
3 0

Answer:

The ladder must be placed at a distance of 33.2 feet from the bottom of the building

Step-by-step explanation:

From what we have here, we are looking at a right angled triangle with the hypotenuse which is the length of the ladder

The height of the child is 50 feet from ground level

So we need to get the third side of the triangle

We can get this by considering the use of Pythagoras’ theorem

This will give us the length of the third side of the triangle

From Pythagoras’ the square of the hypotenuse is equal the sum of the squares of the two other sides

Let the unknown side be x

Thus;

60^2 = 50^2 + x^2

x^2 = 60^2 - 50^2

x^2 = (60-50)(60+50)

x^2 = (10)(110)

x^2 = 1100

x = square root of 1100

x = 33.166

To the nearest tenth, this is 33.2 feet

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Answer:

False

Step-by-step explanation:

It is given that Noah thinks :

9x - 2x + 4x = 3x   as the subtraction sign after 9x tells us to subtract everything that comes after 9x.

This is wrong as according to the BODMAS rule, we have to do the addition operation first and then followed by subtraction operation.

That is

⇒ 9x - 2x + 4x

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Therefore the answer to the equation is 11x and not 3x.

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3 years ago
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omeli [17]

Answer:

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Step-by-step explanation:

2x + y = 12

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this os all I really under stand lol sorry!

6 0
3 years ago
Read 2 more answers
Q1.Simplify:
solniwko [45]

\textbf{(i)}\\\\\{1^3 +2^3 \} \times \left(\dfrac 13 \right)^2\\\\=(1+8) \left(\dfrac 19 \right)\\\\=9\left(\dfrac 19 \right)\\\\=1\\\\

\textbf{(ii)}\\\\\{5^{-1}\times 4^{-1}\}^2\\\\=\left(5^{-1} \right)^2 \times \left(4^{-1} \right)^2~~~~~~~~~~~;[(ab)^m = a^mb^m]\\\\=5^{-2}\times 4^{-2}~~~~~~~~~~~~~~~~~~~~;[(a^m)^n = a^{mn}]\\\\=\dfrac 1{5^2} \times \dfrac 1{4^2}~~~~~~~~~~~~~~~~~~~~~~;\left[a^{-m} = \dfrac 1{a^m},~ a\neq 0 \right]\\\\=\dfrac{1}{400}\\\\=0.0025\\\\

\textbf{(iii)}\\\\\left\{ \left(\dfrac 13 \right)^{-2}  \times \left( \dfrac 12 \right)^{-2}\right\}\div \left(\dfrac 14 \right)^{-3}\\\\\\=\left( \dfrac 13 \times \dfrac 12 \right)^{-2} \div\left(4^{-1}\right)^{-3}\\\\\\=\left(\dfrac 16 \right)^{-2} \div 4^3\\\\\\=\left(6^{-1} \right)^{-2}\div 4^3\\\\\\=6^2 \div 4^3\\\\\\=36\div 64\\\\\\=\dfrac{9}{16}\\\\\\=0.5625

6 0
2 years ago
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I need help with this please
stiv31 [10]
Your equation is 33B-8 pls give brainliest trying to rank up if this is correct
6 0
3 years ago
Find the exact value of x
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<span>What does lol, idk, and ttyl mean? I am serious Answer me and I will answer you
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