Answer:
Klorina's rate in still water is 4.5 km/h
Current's rate is 0.5 km/h
Step-by-step explanation:
Let
x km/h = Klorina's rate in still water
y km/h = current's rate
<u>With the current (current helps):</u>
Distance = 10 km
Time = 2 hours
Rate = x + y km/h
<u>Against the current:</u>
Distance = 8 km
Time = 2 hours
Rate = x - y km/h
Divide both equations by 2:
Add these equations:
Subtract these two equations:
By remainder theorem:
f(x) = x³ - 2
factor, x - 1 = 0
x = 1,
Remainder = f(1)
f(x) = x³ - 2
f(1) = 1³ - 2 = 1 - 2 = -1.
Hence remainder is = -1.
Answer:
16y + 32
Step-by-step explanation:
Expand each term.
(y+6)² - (y-2)²
= (y+6)(y+6) - (y-2)(y-2)
= y² + 12y + 36 - (y² - 4y + 4)
Subtract the second group by changing each term's signs
= y² + 12y + 36 - y² + 4y - 4
Collect like terms
= 16y + 32
Domain is [-10,∞)
2 is included , only at x=2 new function begins
Range is the values of y , so range is [-7]∪[-4,6
I think, it should be like this.
