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Bingel [31]
3 years ago
8

A 53.3 kg woman slides down a 35.0° hill with an acceleration of 4.10 m/s. What is the friction force acting on the woman?

Physics
1 answer:
lorasvet [3.4K]3 years ago
5 0

Answer:

I attached an image that should help.

Explanation:

Check it out.

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What do microwaves have in common with light waves?
frozen [14]

Microwaves and light waves ... as well as radio, X-rays,
ultraviolet rays, gamma rays, etc. ... are waves of
electromagnetic radiation.  The difference is in their
frequency/wavelength.

8 0
3 years ago
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A car accelerates uniformly from rest and reaches a speed of 21.9 m/s in 8.99 s. Assume the diameter of a tire is 57.5 cm. (a) F
Marat540 [252]

Answer:

Explanation:

initial velocity, u = 0 m/s

time, t = 8.99 s

final velocity, v = 21.9 m/s

diameter of tyre, D = 57.5 cm

(a) Let a is the acceleration, and n be the number f revolutions made by the tyre.

Use first equation of motion

v = u + at

21.9 = 0 + a x 8.99

a = 2.44 m/s²

Use third equation of motion

v² = u² + 2 a s

21.9 x 21.9 = 0 + 2 x 2.44 x s

s = 98.28 m

Circumference of wheel, S = π x D = 3.14 x 0.575 = 1.8055 m

number of revolutions, n = distance / circumference

n = 98.28 / 1.8055

n = 54.4

7 0
3 years ago
What is the typical treatment for Hodgkin's disease?
Evgesh-ka [11]

Answer:

Pretty sure its D.

radiation, chemotherapy, and bone marrow transplant

Explanation:

7 0
3 years ago
Two balls with equal masses, m, and equal speed, v, engage in a head on elastic collision. what is the final velocity of each ba
Allushta [10]
The collision is elastic. This means that both momentum and kinetic energy are conserved after the collision.

- Let's start with conservation of momentum. The initial momentum of the total system is the sum of the momenta of the two balls, but we should put a negative sign in front of the velocity of the second ball, because it travels in the opposite direction of ball 1. So ball 1 has mass m and speed v, while ball 2 has mass m and speed -v:
p_i = p_1-p_2 = mv-mv =0
So, the final momentum must be zero as well:
p_f = 0
Calling v1 and v2 the velocities of the two balls after the collision, the final momentum can be written as
p_f = mv_1 + mv_2 = 0
From which
v_1 = -v_2

- So now let's apply conservation of kinetic energy. The kinetic energy of each ball is \frac{1}{2} mv^2. Therefore, the total kinetic energy before the collision is
K_i = \frac{1}{2} mv^2 +  \frac{1}{2} mv^2 = mv^2
the kinetic energy after the collision must be conserved, and therefore must be equal to this value:
K_f = K_i = mv^2 (1)
But the final kinetic energy, Kf, is also
K_f =  \frac{1}{2} mv_1^2 +  \frac{1}{2}mv_2^2
Substituting v_1 = -v_2 as we found in the conservation of momentum, this becomes
K_f = mv_2 ^2
we also said that Kf must be equal to the initial kinetic energy (1), therefore we can write 
mv_2^2 = mv^2

Therefore, the two final speeds of the balls are
v_2 = v
v_1 = -v_2 = -v

This means that after the collision, the two balls have same velocity v, but they go in the opposite direction with respect to their original direction.

8 0
3 years ago
All objects in the universe radiate some form of energy.<br> a. True<br> b. False
Harrizon [31]

That's true.  The only way to stop an object from radiating energy
is to cool it to absolute zero.  Since the temperature of space is
roughly 3 degrees above absolute zero, the atoms or molecules
of every object have some kinetic energy, and the object radiates
some heat. 

Of course it also absorbs heat at the same time, mostly from the
huge number of stars shining on it.

3 0
4 years ago
Read 2 more answers
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