Answer:
Ca3(PO4)2 + 3H2SO4 —> 3CaSO4 + 2H3PO4
The coefficients are 1, 3, 3, 2
Explanation:
Ca3(PO4)2 + H2SO4 —> CaSO4 + H3PO4
From the above equation,
There are 3 atoms of Ca on the left and 1 atom of Ca on the right. To balance Ca, put 3 in front of CaSO4 as shown below
Ca3(PO4)2 + H2SO4 —> 3CaSO4 + H3PO4
Now, we have 3 atoms of SO4 on the right and 1atom on the left. To balance SO4, put 3 in front of H2SO4 as shown below:
Ca3(PO4)2 + 3H2SO4 —> 3CaSO4 + H3PO4
Looking closely, there are 6 atoms of H on the left and 3 on the right. Therefore, it is balanced by by putting 2 in front of H3PO4 as shown below:
Ca3(PO4)2 + 3H2SO4 —> 3CaSO4 + 2H3PO4
The coefficients are 1, 3, 3, 2
Answer: the oxidation of the copper (it turning green)
Explanation:
Answer:
1.05 x 10^-6
Explanation:
Lambda = c / f
f if frequency
c is intensity of light
lambda = 3 x 10^8 / 2.85 x 10^14
= 1.05 x 10 ^-6
Explanation:
Al2O3
16=molar mass of one oxygen atom
Number of moles: mass/molar mass
Mol of O3: 19÷(16*3) = 0.40 g/mol
mole ratio
0.40: 3 (oxygen)
0.27: 2 (aluminum)
Mass = molar mass*mole
0.27*(27*3)= 21.87g
Using pH to determine [H+]
10^-pH= 10^-2.45 = 2.1 x 10^-3
<span>
Now,
Ka=[H=][A-]/[HA] </span>
<span>So,
(2.1 x 10^-3)^2/0.0136 - (2.1 x 10^-3) </span>
<span>Ka=2.5 x 10^4</span>