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Phoenix [80]
3 years ago
12

What is the molar mass of a substance?

Chemistry
1 answer:
OlgaM077 [116]3 years ago
4 0

oops pls forgive me I accidentally did the wrong question.

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What is the numbers of molecules for 65.8g of CO2?
baherus [9]

Answer:

One gram of carbon dioxide contains 13.6 x 10²¹ number of molecules.

Explanation:

4 0
2 years ago
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What description best describes both mirrors and lenses?
WITCHER [35]
Mirrors reflect light and lenses refract light.
Mirrors form images by reflecting all light that is incident on their surface, which allows us to see the reflections of objects in mirrors. Lenses, on the other hand, bend light and allow it to pass through them. The bending of light is used to form enlarged images, and for many other purposes as well.
7 0
3 years ago
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How many mL of 0.25 M NaOH would have 0.18 moles of NaOH?
8_murik_8 [283]

Answer:

720 mL

Explanation:

To answer this problem we'll use the <em>definition of molarity</em>:

  • Molarity = moles / liters

With that in mind we can <u>calculate the volume in liters</u>:

  • 0.25 M = 0.18 moles / liters
  • liters = 0.72 L

Finally we<u> convert liters to mL</u>:

  • 0.72 L * 1000 = 720 mL

Thus 720 mL of 0.25 M NaOH would have 0.18 moles of NaOH.

5 0
3 years ago
On average what is the time between collisions of a xenon atom at 300 K and (a) one torr pressure; (b) one bar pressure.
Amanda [17]

Answer:

(a). 132 × 10^-9 s = 132 nanoseconds.

(b)..176.5 pico-seconds.

Explanation:

(a). At one torr, the first thing to do is to find the speed and that can be done by using the formula below;

Speed = [ (8 × R × T)/ Mm × π]^1/2.

Where Mm = molar mass, T = temperature and R = gas constant.

Speed= [ ( 8 × 8.314 × 300)/ 131.293 × π × 10^-3)^1/2. = 220m/s.

The next thing to do now is to calculate for the degree of collision which can be calculated by using the formula below;

Degree of collision = √2 × π × speed × d^2 × pressure/ K × T.

Note that pressure = 1 torr = 133.32 N/m^2 and d = collision diameter.

Degree of collision = √2 × π × 220 × (4.9 × 10^-10)^2 × 133.32/ 1.38 × 10^-23 × 300.

Degree of collision = 7.55 × 10^6 s^-1.

Thus, 1/ 7.55 × 10^6. = 132 × 10^-9 s = 132 nanoseconds.

(b). At one bar;

1/10^5 × 10^3 × 56.65 = 1.765 × 10^-10 = 176.5 pico-seconds.

6 0
3 years ago
Which element would have this representation: 43 ? 21 Question 4 options: Technetium Scandium Titanium Cobalt
Artyom0805 [142]

Answer:

The naswer to your question is Scandium

Explanation:

43 means the atomic mass is normally presented as a power

21 means atomic number is always a subscript

                   ₂₁ ? ⁴³

Technetium             ₄₃Tc⁹⁸

Scandium                 ₂₁Sc⁴⁴      

Titanium                   ₂₁Ti⁴⁷

Cobalt                      ₂₇Co⁵⁹

5 0
3 years ago
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