Answer:
Explanation:
Given data
Space vehicle speed=5425 km/h relative to earth
The rocket motor speed=81 km/h and mass 4m
The command has mass m
From the conservation of momentum as the system isolated
Since the motion in on direction we can drop the unit vector direction
Where M is the mass of space vehicle which equals to sum of the motors mass and command mass.
The velocity of the motor relative to the earth equals the velocity of the motor relative to command plus the velocity of the command relative to earth
Where Vmc is the velocity of motor relative to command
This yields
Substitute the given values
distance d = 5 km = 5 x 1000 m = 5000 m
time taken = 25 minute = 25 x 60 sec = 1500 sec
average velocity V = d/t
V = 5000/1500
V = 3.33 m/s towards east
An object that weighs 100 tons and is floating is displacing exactly 100 tons of the fluid, and the buoyant force on it is 100 tons. The vertical forces on it are balanced (add up to zero), and that's why it isn't accelerating up or down.
The ammeter will indicate that a current is flowing in the second coil only when current changes in the first coil.
<h3>
Induced emf</h3>
An emf is induced in a coil placed in a magnetic field when a current carrying conductor moves in the field.
emf = NdФ/dt
where;
- dФ is change in flux of the field
- N is number of turns
- dt is change in time
Thus, the ammeter will indicate that a current is flowing in the second coil only when current changes in the first coil.
Learn more about induced emf here: brainly.com/question/13744192
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Answer:
Explanation:
Q₂ is at the origin and Q₁ is at 12 cm on x -axis
Force between Q₁ and Q₂
= K x Q₁ x Q₂ / .12 where k is a constant equal to 9x 10⁹
Force F = 9 x 10⁹ x Q₁ x Q₂ / .12²
= 625 x 10⁹ x Q₁Q₂ N
This is the force each one exerts on other . So electric force on Q₂ due to Q₁ is 625 x 10⁹ x Q₁Q₂ N . Its direction is towards left as both will repel each other.
b)
Electric field due to charge Q₂ at - 2 cm
= 9 x 10⁹ x Q₂ / .02²
= 22500 x 10⁹ x Q₂ N/C , towards left .
Electric field due to charge Q₁ at - 2 cm
= 9 x 10⁹ x Q₁ / .14²
= 459.18 x 10⁹ x Q₁ N/C , towards left
As both the fields are to the same direction
Net field = 75 x 10⁹ x Q₂ + 459.18 x 10⁹ x Q₁
10⁹ ( 22500 x Q₂ + 459.18 x Q₁ ) N/C .
Direction will be towards left.
