Question

Find the total pressure (in atm) of a mixture that contains 3 gases with the following partial pressures. Gas A is 4.2atm, Gas B is 780 mmHg, Gas C is 250.00kPa

Answer 1

Answer: The total pressure of given mixture that contains 3 gases is 7.68 atm.

Explanation:

Given: Partial pressure of gases is:

Gas A = 4.2 atm

Gas B = 780 mm Hg

Convert mm Hg into atm is as follows.

$1 mm Hg = 0.00131579 atm\\780 mm Hg = 780 mm Hg \times \frac{0.00131579 atm}{1 mm Hg}\\= 1.02 atm$

Gas C = 250 kPa

Convert kPa into atm as follows.

$1 kPa = 0.00986923 atm\\250 kPa = 250 kPa \times \frac{0.00986923 atm}{1 kPa}\\= 2.46 atm$

Total pressure is the sum of partial pressures of gases present in the mixture.

Therefore, total pressure of given mixture is calculated as follows.

$P_{total} = P_{A} + P_{B} + P_{C}\\= 4.2 atm + 1.02 atm + 2.46 atm\\= 7.68 atm$

Thus, we can conclude that the total pressure of given mixture that contains 3 gases is 7.68 atm.