The graphed line is y = 1/3x + 2
In order to solve for this, we need to start by finding the slope. To find the slope, we start by selecting two points on the graph. We'll use (0, 2) and (6, 4).
m(slope) = (y2 - y1)/(x2 - x1)
m = (4 - 2)/(6 - 0)
m = 2/6
m = 1/3
Now that we have this, we can use a point and slope intercept form to find the intercept.
y = mx + b
4 = (1/3)(6) + b
4 = 2 + b
2 = b
And we can use the slope and intercept to model the equation as y = 1/3x + 2
Answer:is it a y intercept
Step-by-step explanation:
<u>Answer </u><u>:</u><u>-</u>
Given inequality ,
- -5x +3y > 12
- 3y > 5x + 12
- y > 5/3x + 12/3
- y > 5/3x + 4
From the options ,
<u>When </u><u>x </u><u>is </u><u>3</u><u> </u><u>and </u><u>y </u><u>=</u><u> </u><u>9</u>
- y >1* 5 + 4
- y > 5 +4
- 9> 9 ( Not possible )
<u>When</u><u> </u><u>x </u><u>is </u><u>-</u><u>5</u><u> </u><u>y</u><u> </u><u>is </u><u>5</u><u> </u>
- y > 5/3*-5 + 4
- y > -8.3 + 4
- 5 > -3.7 ( Possible )
<u>When </u><u>x </u><u>is </u><u>3</u><u> </u><u>y </u><u>is </u><u>-</u><u>6</u><u> </u>
- y > 5 + 4
- -6 > 9 ( Not possible )
<u>When </u><u>x </u><u>is </u><u>-</u><u>2</u><u> </u><u>y </u><u>is </u><u>-</u><u>5</u><u> </u>
- y > -3.33 + 4
- -5 > -0.67 ( Possible )
<u>When </u><u>x </u><u>is </u><u>2</u><u> </u><u>y </u><u>is </u><u>8</u><u> </u>
- y > 3.33 + 4
- 8 > 7.77 ( possible )
<u>When</u><u> </u><u>x </u><u>is </u><u>-</u><u>6</u><u> </u><u>y </u><u>is </u><u>0</u><u> </u>
- y > -10 +4
- 0 > -6 ( possible )
Answer:
3x + 14
Step-by-step explanation:
Just add them together.
2x + 5 + x + 9
= 3x + 14
<span>The curve formed by a quadratic equation is called a PARABOLA</span>
