Solve the right triangle. Round decimal answers to the nearest tenth.

Mathematics

2 answers:

eimsori [14]2 years ago

8 0

AB² = AC²+BC²

AB² = 9²+12²

AB²= 225

AB= 15

SinA = 12/15

A = Sin-¹(0.8)

M`A = 53°

M`B = 90- A = 90-53= 37°

shusha [124]2 years ago

8 0

Answer:

AB = 15

m ∠A = 53.1°

m ∠B = 36.9°

Step-by-step explanation:

$AB^2 = AC^2+CB^2 \\AB^2 = 9^2 + 12^2 = 81 + 144 = 225\\AB = \sqrt{225} = 15$

$sin A = \frac{opposite}{hypotenuse} = \frac{12}{15}\\\\A = sin^{-1} (\frac{12}{15})\\\\$

A = 53.13

m∠A = 53.1°

∠A + ∠B + ∠C = 180°

53.1 +∠B + 90 = 180

∠B = 180 - 90 - 53.1 = 36.9°

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larisa86 [58]

The complete question in the attached figure

we know that
(see the attached figure n 2 to understand the problem)
[the surface area of one prism]=2*[x*x]+2*[x*y]+2*[x*y]----> 2x²+4xy
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now
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we compare the value that JD says with the real value
(8x²+16xy) > (6x²+16xy)
the value that JD says is greater in comparison with the real value
This is because JD should also subtract the areas of eight hidden surfaces.

the answer is
JD should also subtract the areas of eight hidden surfaces