Solve the right triangle. Round decimal answers to the nearest tenth.

Mathematics

2 answers:

eimsori [14]3 years ago

8 0

AB² = AC²+BC²

AB² = 9²+12²

AB²= 225

AB= 15

SinA = 12/15

A = Sin-¹(0.8)

M`A = 53°

M`B = 90- A = 90-53= 37°

shusha [124]3 years ago

8 0

Answer:

AB = 15

m ∠A = 53.1°

m ∠B = 36.9°

Step-by-step explanation:

$AB^2 = AC^2+CB^2 \\AB^2 = 9^2 + 12^2 = 81 + 144 = 225\\AB = \sqrt{225} = 15$

$sin A = \frac{opposite}{hypotenuse} = \frac{12}{15}\\\\A = sin^{-1} (\frac{12}{15})\\\\$

A = 53.13

m∠A = 53.1°

∠A + ∠B + ∠C = 180°

53.1 +∠B + 90 = 180

∠B = 180 - 90 - 53.1 = 36.9°

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