3 years ago

Please help! Will mark BRAINLIEST!

Mathematics

1 answer:

Softa [21]3 years ago

7 0

your awnser was hard and complicated but i think i got it 7214.485x^10y^10

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TEST DUE BY 12 I NEED HELP

Bumek [7]

Answer:

study

Step-by-step explanation:

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3 years ago

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Naily [24]

$\Delta\ \textgreater \ 0\\\\

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m^2\ \textgreater \ 64\\
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3 years ago

What is the imgae point of (-2,-3) after a translation right 2 units and 4 up units?

kherson [118]

the image point of (-2,-3) after a translation right 2 units and 4 up units is (0,1) .

<u>Step-by-step explanation:</u>

Here we have , to find the image point of (-2,-3) after a translation right 2 units and 4 up units . Let's find out:

Initially we have the point as (-2,-3) , Following transformations are done :

a translation right 2 units :

The point is (-2,-3) , let $(x,y)=(-2,-3)$ . Translation is 2 units right , means there is change in x coordinate by +2 , i.e.

⇒ $(x,y)=(-2,-3)$

⇒ $(x+2,y)=(-2+2,-3)$

⇒ $(x+2,y)=(0,-3)$

a translation 4 up units:

The point is (0,-3) , let $(x,y)=(0,-3)$ . Translation is 4 units up , means there is change in y coordinate by +4 , i.e.

⇒ $(x,y)=(0,-3)$

⇒ $(x,y+4)=(0,-3+4)$

⇒ $(x,y+4)=(0,1)$

Therefore , the image point of (-2,-3) after a translation right 2 units and 4 up units is (0,1) .

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3 years ago

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alekssr [168]

The answer is d because if you multiply-5x2 and then subtract 1 you get -11

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