Answer:
2.56 moles of nitrogen was released.
Explanation:
We'll begin by calculating the final moles of nitrogen in the canister. This can be obtained as follow:
Initial mole (n₁) = 3.2 moles
Initial volume (V₁) = 1.5 L
Final volume (V₂) = 0.3 L
Final mole (n₂) =?
V₁/n₁ = V₂/n₂
1.5 / 3.2 = 0.3 / n₂
Cross multiply
1.5 × n₂ = 3.2 × 0.3
1.5 × n₂ = 0.96
Divide both side by 1.5
n₂ = 0.96 / 1.5
n₂ = 0.64 mole
Finally, we shall determine the number of mole of nitrogen that was released. This can be obtained as follow:
Initial mole (n₁) = 3.2 moles
Final mole (n₂) = 0.64 mole
Amount released =?
Amount released = n₁ – n₂
Amount released = 3.2 – 0.64
Amount released = 2.56 moles
Thus, 2.56 moles of nitrogen were released.
