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fenix001 [56]
2 years ago
12

How many grams of AgNO3 (MM=169.87) are needed to prepare 0.125 M solution in 250 mL of water?

Chemistry
1 answer:
ollegr [7]2 years ago
8 0

Answer:

<em>Correct answer-C 5.3g</em>

Explanation:

M<em><u>olarity = no. of moles of solute/ volume of of solution in litre</u></em>

<em><u>olarity = no. of moles of solute/ volume of of solution in litreno of moles of solute = 0.125×0.25=0.03125</u></em>

<em><u>olarity = no. of moles of solute/ volume of of solution in litreno of moles of solute = 0.125×0.25=0.03125one mole AgNO3 weighs 169.87 gm,</u></em>

<em><u>olarity = no. of moles of solute/ volume of of solution in litreno of moles of solute = 0.125×0.25=0.03125one mole AgNO3 weighs 169.87 gm,so the mass of 0.03125 moles of AgNO3 = 0.03125×169.87= </u></em><em><u>5.3084g</u></em>

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Explanation:

Density is a quantity that expresses the relationship between the mass and the volume of a body, so it is defined as the quotient between the mass and the volume of a body:

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