Answer:
Au3+(aq) + 3Cu+(aq) → Au(s) + 3Cu2+(aq)
1.35 V
Explanation:
Given that the reduction potential of
Cu^2+(aq) + e- -----> Cu^+(aq) is +0.15 V
While the reduction potential of
Au3+(aq) + 3 e- -----> Au(s) is + 1.50V
It is clear that the Cu^+(aq)/Cu^2+(aq) system is the anode while Au^3+(aq)/Au(s) system is the cathode based on the reduction potentials shown above. The number of electrons transferred (n) =3
E°cell = E°cathode - E°anode
E°cell= 1.50-0.15
E°cell= 1.35 V
Ammonia is NH3. The molar mass of NH3 is 17.0307g.
(1.2*10^3)/17.0307=70.46 moles of NH3.
If you are using significant figures, it is 70. moles of NH3.
Answer: 
Explanation:
You need to know the conversion factor first in order to solve this. Any gas occupies 22.4L per mol.
of nitrogen gas.
That is false because every type of plastic can biodegrade
