Answer:
The frequency must be: 
Explanation:
If the work function of the metal (
) is 3 eV, then we can use the formula for the kinetic energy of an ejected electron:
considering for the minimum KE = 0, and using the Plank constant h in eV s as: 4.14 * 10 ^(-15) eV s, to solve for the frequency:
Alpha > Beta > Gamma
Explanation:
Alpha particles are the heaviest radiation whereas gamma rays are the lightest.
An alpha particle closely resembles a helium particle.
Beta particles are similar to electrons in nature
Gamma rays have no weight. They are just rays.
Alpha particles have a mass of 4.0012amu which is that of helium
Beta particles have a mass of 5.5 x 10⁻⁴ amu
Gamma rays have no mass.
Learn more:
Electromagnetic radiations brainly.com/question/6818046
#learnwithBrainly
Ok to distinguish the difference you just find out why there's science lol.......anyways.....Mass is the amount of space being taken up in a certain place (or possibly all the world) and weight is the heaviness of an person or thing kk??? also if my answer was best, plzz give brainliest (trust me i need it) Have a great day and Christmas (if u celebrate it)!!
Answer:
0.0814 Wb
Explanation:
L = length of the rectangular coil = 5 cm = 0.05 m
w = width of rectangular coil = 7 cm = 0.07 m
A = Area of the coil = L w = 0.05 x 0.07 = 35 x 10⁻⁴ m²
B = magnitude of uniform magnetic field = 0.55 T
θ = angle of axis of coil with magnetic field = 65°
Magnetic flux through the coil is given as
Φ = N B A Cosθ
Φ = (100) (0.55) (35 x 10⁻⁴ ) Cos65
Φ = 0.0814 Wb
From Literature:
The amount of energy in the photons is given by this equation:
E = hf
where E = energy
h = Planck's constant = 6.63 * 10^-34 Joule seconds
f = frequency of the light, Hz
Given:
E= 3.00 eV and Planck's constant
To solve for the frequency, E = 3.00 eV
1 electronvolt = 1.60218 x 10^-19 Joules
3 * 1.60218 x 10^-19 Joules = 6.63 * 10^-34 Joule seconds * f
f = 7.25 x 10^14 /second or hertz
Therefore, the threshold frequency of the material is 7.25 x 10^14 Hertz.
