At the bottom of the tank :
P = ρgH
P = (1000 kg/m³)(10 m/s²)(1 m)
P = 10000 N/m²
F = P • A
F = (10000 N/m²)(1 m²)
F = 10000 N
At the side of the tank :
Pav = ½ρgH
Pav = ½(1000 kg/m³)(10 m/s²)(1 m)
Pav = 5000 N/m²
F = P • A
F = (5000 N/m²)(1 m²)
F = 5000 N
The minimum coefficient of static friction between the pavement and the tires is 0.69.
The given parameters;
- <em>radius of the curve, r = 90 m</em>
- <em>angle of inclination, θ = 10.8⁰</em>
- <em>speed of the car, v = 75 km/h = 20.83 m/s</em>
- <em>mass of the car, m = 1100 kg</em>
The normal force on the car is calculated as follows;
The frictional force between the car and the road is calculated as;
The net force on the car is calculated as follows;
Thus, the minimum coefficient of static friction between the pavement and the tires is 0.69.
Learn more here:brainly.com/question/15415163
The wavelength for C1 note is 10.40 m, for A6 note is 0.193 m and for B7 note 0.086 m.
Answer:
Explanation:
Since, wavelength, frequency and speed of sound waves are related to each other, we can determine a single parameter with the help of other two parameters. So in this case, the frequency of different notes are given along with their common speed. So as the frequency is inversely proportional to the wavelength then in this case, the wavelength of the notes will be maximum for C1 and minimum for 3951.1 Hz.
Wavelength = Speed / Frequency
Wavelength for C1 note = 340 / 32.7 =10.40 m
Similarly, the wavelength for A6 note = 340/1760=0.193 m
And, the wavelength for B7 note = 340/3951.1 = 0.086 m
So, the wavelength for C1 note is 10.40 m, for A6 note is 0.193 m and for B7 note 0.086 m.
Answer: v = 20 m/s
Explanation: Solution:
Use the formula of Kinetic Energy and derive for v:
KE = 1/2 mv²
To find v:
v = √ 2 KE / m
= √ 2 ( 100000 J ) / 500 kg
= √ 400 m/s
= 20 m/s
