According to newton's second law of motion F=ma , but here we have to find a so a=f/m ,a=8.11/1028=0.007m/sec² or 7×10‐3m/sec2
Answer:
The torque must be applied to the wheel is 15.7 N-m.
Explanation:
Given that,
Mass of the wheel of cylinder, m = 50 kg
Diameter of the wheel, d = 1 m
Radius, r = 0.5 m
Initial speed off the wheel is 0
Final angular speed of the wheel, 120 rev/min = 12.56 rad/s
Angular displacement, 
The torque is given by :

So, the torque must be applied to the wheel is 15.7 N-m.
You can download
the answer here
bit.
ly/3gVQKw3
All of them at the same time if they start off at the same temperature and same volume