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Reika [66]
3 years ago
12

I need help :(((((((((((

Physics
1 answer:
Alex Ar [27]3 years ago
6 0

Answer:

4- false

5- false (i think..)

Explanation:

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An airplane is flying in a horizontal circle at a speed of 92.1 m/s. The 55.6 kg pilot does not want his radial acceleration to
Fudgin [204]

Answer:

 r = 102.43 m

Explanation:

Newton's second law for this case is

              F = ma

Where the acceleration is centripetal

            a = v² / r

            r = v² / a

They indicate that the radial acceleration is 8.45 g

           r = v² / 8.45 g.

           r = 92.1² / 8.45 9.8

           r = 102.43 m

7 0
3 years ago
Why are large astronomical bodies round
-Dominant- [34]
<span>Matter of all types have gravity, which causes it to attract to each other. The most efficient way for all this matter to congregate is the sphere. As they consolidate, they form the shape. As they compress, temperatures in the center of the mass start to go up and if it hits the proper point, it can ignite and become a star.</span>
7 0
3 years ago
Read 2 more answers
Suppose a scoentist was able to construct a barometer with a liquid being denser than mercury , then how high would the liquid r
ki77a [65]

Answer:

the liquid has less height than the mercury

      h_{ liquid} = \frac{\rho_{Hg} }{\rho_{liqid}}  \  h_{Hg}

Explanation:

The pressure as a function of the height is given by

        P = ρ g h

where ρ is the density of the liquid, g the acceleration of gravity and h the height reached by the column of the liquid

In that case they say that the pressure is the standard one that is P = 1.01 10⁵ Pa = 760 mmHg

The first way to give the pressure is in SI units and the second way is the height that the mercury column reaches

In the case of building a barometer with a liquid that has a density greater than that of mercury

            ρ_liquid > ρ_Hg

             

the pressure

              P =ρ_lquid g h_liquid

if we have the same pressure

            ρ_{Hg} g h_{Hg} = ρ_{liquid}  g h_{liquid}

            h_{ liquid} = \frac{\rho_{Hg} }{\rho_{liqid}}  \  h_{Hg}

therefore the liquid has less height than the mercury

7 0
3 years ago
Birdman is flying horizontally at a
den301095 [7]

Answer:

68 m

Explanation:

Given that the horizontal velocity of the birdman = 17 m/s and

the height, h= 78 m.

The gravitational force is acting in the downward direction, so it will not change the horizontal speed.

The horizontal speed will remains be constant and will be equal to the initial horizontal speed of the turd.

Initially, the turd was also flying horizontally with the birdman, so the initial velocity of the turd is the same as the horizontal velocity of the birdman, i.e In the horizontal direction, u_0=17 m/s.

In the vertical direction, u = 0,

The distance to be traveled, in the direction of application of force, is equals to the height of the turd, i.e

s= 78 m

Let t be the time taken to cover a distance of 78 m.

Now, applying the equation of motion in the vertical direction,

s=ut+\frac 12 at^2

where u is the initial velocity and a is the acceleration due to gravity in the direction of displacement,s.

Here, a=g=9.81 m/s^2, so

78=0\times t +\frac 12 (9.81)t^2

\Rightarrow t^2=(78\times2)/9.81

\Rightarrow t = 4 seconds.

Hence, the time taken to reach the ground is 4 seconds.

As the horizontal speed, u_0=17 m/s, is constant throughout the journey, so

the horizontal distance covered by turd

= u\times t

= 17 \times 4 = 68 m.

So, the distance of landing from the start of the field is 68 m as the birdman releases a turd directly  above the start of the field.

Hence, the robot must hold the bucket at a distance of 68 m from the start of the field.

5 0
3 years ago
A toy cannon uses a spring to project a 5.24-g soft rubber ball. The spring is originally compressed by 5.01 cm and has a force
salantis [7]

Answer:

Speed will be equal to 1.40 m/sec

Explanation:

Mass of the rubber ball m = 5.24 kg = 0.00524 kg

Spring is compressed by 5.01 cm

So x = 5.01 cm = 0.0501 m

Spring constant k = 8.08 N/m

Frictional force f = 0.031 N

Distance moved by ball d = 15.8 cm = 0.158 m

Energy gained by spring

KE=\frac{1}{2}kx^2=\frac{1}{2}\times 8.08\times 0.0501^2=0.0101J

Energy lost due to friction

W=Fd=0.031\times 0.158=0.0048J

So remained energy to move the ball = 0.0101 - 0.0048 = 0.0052 J

This energy will be kinetic energy

\frac{1}{2}mv^2=0.0052

\frac{1}{2}\times 0.00524\times v^2=0.0052

v = 1.40 m/sec

7 0
3 years ago
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