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MakcuM [25]
3 years ago
5

CAN PEOPLE PLEASE HELP, I NEED TO GET TO THE NEXT LEVEL OR WHATEVER ITS CALLED BUT I NEED 5 BRAINLIEST IN 2 DAYS, I ALREADY HAVE

7 BUT THAT DOSENT COUNT IG, IF YOU HELP ILL RETURN THE FAVOR AND GIVE YOU BRAINLIEST ON YOUR AWENSERS OR QUESTIONS........ ILL AWENSER ONE OF YOUR QUESTIONS AND YOU MAKE ME BRAINLIEST? THXX
Physics
2 answers:
Vilka [71]3 years ago
8 0

Answer:

yes you can go on your account

lapo4ka [179]3 years ago
6 0

Answer:

answer the question i have asked go to my account

Explanation:

can i get brainliest

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Why the weight of the body varries from place to place on the earth's surface ​
Scorpion4ik [409]

Answer:

mass of the body is constant as it is property of body, but weight is product of acceleration due to gravity and mass, which may vary from place to place because acceleration due to gravity is different for different places.

5 0
3 years ago
Read 2 more answers
A string attached to an airborne kite is maintained at an angle of 41 degrees with the horizontal. If a total of 152 m of string
satela [25.4K]

Answer:

The  horizontal displacement is  Adj  =  114.71 \ m

Explanation:

From the question we are told that  

    The  angle at which the string is maintained is  \theta  =  41 ^o

      The length of string reeled in is  l  = 152 \ m

     

Using the SOHCAHTOA formula

   We have that the hypotenuse(Hyp) is  l  =  152

Hence the  horizontal displacement of the kite  which is the Adjacent(Adj)  can be evaluated as  

     cos \theta  =  \frac{Adj}{Hyp }

substituting values

     cos(41)  =  \frac{Adj}{152}

=>   Adj  =  114.71 \ m

3 0
3 years ago
How much work is required to move
slega [8]
<span>So we want to know how much work is needed to move a charge Q=3C for a distance r=0.01m trough a potencial difference U=9V. Work of electric potential is defined as W=Q*U and we can now simply put in the numbers. We get: W=3C*9V=27J. So the correct answer is (2) 27J. </span>
4 0
3 years ago
1. 412.9 g of dry ice sublimes at room temperature. a. What’s changing? --- sublimation b. What constant will you use? ----- 25.
hoa [83]

1. 236 kJ

a. The phase (or state of matter) of the substance: from solid state to gas state (sublimation)

b. The enthalphy of sublimation, given by: \lambda=571 J/g

c. The equation to use will be Q=m\lambda, where m is the mass of dry ice and \lambda is the enthalpy of sublimation

d. The energy is being absorbed, because the heat is transferred from the environment to the dry ice: as a consequence, the bonds between the molecules of dry ice break and then move faster and faster, and so the substance turns from solid into gas directly.

e. The amount of energy being transferred is

Q=m\lambda=(412.9 g)(571 J/g)=2.36\cdot 10^5 J=236 kJ

2.  165 kJ

a. The phase (or state of matter) of the substance: from gas state to liquid state (condensation)

b. The latent heat of vaporisation of water, given by \lambda=2260 J/g

c. The equation to use will be Q=m\lambda, where m is the mass of steam that condenses and \lambda is the latent heat of vaporisation

d. The energy is being released, since the substance turns from a gas state (where molecules move faster) into liquid state (where molecules move slower), so the internal energy of the substance has decreased, therefore heat has been released

e. The amount of energy being transferred is

Q=m\lambda=(72.9 g)(2260 J/g)=1.65\cdot 10^5 J=165 kJ

3. 3.64 kJ

a. Only the temperature of the substance (which is increasing)

b. The specific heat capacity of silver, which is C_s = 0.240 J/gC

c. The equation to use will be Q=m C_s \Delta T, where m is the mass of silver, Cs is the specific heat capacity and \Delta T the increase in temperature

d. The energy is being absorbed by the silver, since its temperature increases, this means that its molecules move faster so energy should be provided to the silver by the surroundings

e. The amount of energy being transferred is

Q=m C_s \Delta T=(39.2 g)(0.240 J/gC)(412.9^{\circ}C-25.9^{\circ}C)=3641=3.64 kJ

4. 89 kJ

a. Both the phase of the substance (from solid to liquid) and then the temperature

b. The latent heat of fusion of ice: \lambda=334 J/g and the specific heat capacity of water: C_s=4.186 J/gC

c. The equation to use will be Q=m\lambda + m C_s \Delta T, where m is the mass of ice, \lambda the latent heat of fusion of ice, Cs is the specific heat capacity of water and \Delta T the increase in temperature

d. The energy is being absorbed by the ice, at first to break the bonds between the molecules of ice and to cause the melting of ice, and then to increase the temperature of the water

e. The amount of energy being transferred is

Q=m\lambda +m C_s \Delta T=(156.3 g)(334 J/g)+(156.3 g)(4.186 J/gC)(56.232^{\circ}C-0^{\circ}C)=8.9\cdot 10^4 J=89 kJ

6 0
3 years ago
Suppose the charges attracting each other in the above situation have an equal magnitude. Find the charge.
LiRa [457]

The force between the two point charge when they are separated by 18 cm is 3 N

<h3>How do I determine the force when they are 18 cm apart?</h3>

Coulomb's law states as follow:

F = Kq₁q₂ / r²

Cross multiply

Fr² = Kq₁q₂

Kq₁q₂ => constant

F₁r₁² = F₂r₂²

Where

  • F₁ and F₂ are the initial and new force
  • r₁ and r₂ are the initial and new distance apart

With the above formula, we can obtain the force between the two point charge when they are 18 cm apart. Details below:

  • Initial distance apart (r₁) = 6 cm
  • Initial force of attraction (F₁) = 27 N
  • New distance apart (r₂) = 18 cm
  • New force of attraction (F₂) =?

F₁r₁² = F₂r₂²

27 × 6² = F₂ × 18²

972 = F₂ × 324

Divide both side by 324

F₂ = 927 / 324

F₂ = 3 N

Thus, the force when they are 18 cm apart is 3 N

Learn more about force:

brainly.com/question/28569085

#SPJ1

7 0
2 years ago
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