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natulia [17]
3 years ago
13

"what is the period of one vibration of this tone?"

Physics
1 answer:
Viktor [21]3 years ago
7 0
The full question is:
On a keyboard, you strike middle C, whose frequency is 256 Hz. What is the period of one vibration of this tone?
The period of a vibration is the time it takes for the particle to make one full oscillation. Frequency is by definition number of full oscillations per unit of time.
When the frequency is expressed in Hz that unit of time is one second.
So there is the following relation between frequency and period:
T=\frac{1}{f}
When we plug in the numbers we get:
T=\frac{1}{256}=0.0039$s
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Find the volume of a sphere of radius 10 mm.
vredina [299]

Answer:

Explanation: This is done using the equation:

\frac{4}{3} π R^{3}

Because the Radius is a know value. We have the following.

\frac{4}{3} π (10mm)^{3}

Which is:

4188.7902 mm

5 0
3 years ago
An apple dropped from the branch of a tree hits the ground in 0.5 s. If the acceleration of the apple during its motion is 10 ms
Ipatiy [6.2K]

Given that,

Time = 0.5 s

Acceleration = 10 m/s²

(I). We need to calculate the speed of apple

Using equation of motion

v=u+at

Where, v = speed

u = initial speed

a = acceleration

t = time

Put the value into the formula

v=0+10\times0.5

v=5\ m/s

(III). We need to calculate the height of the branch of the tree from the ground

Using equation of motion

s=ut+\dfrac{1}{2}gt^2

Put the value into the formula

s=0+\dfrac{1}{2}\times10\times(0.5)^2

s=1.25\ m

(II). We need to calculate the average velocity during 0.5 sec

Using formula of average velocity

v_{avg}=\dfrac{\Delta x}{\Delta t}

v_{avg}=\dfrac{x_{f}-x_{i}}{t_{f}-t_{0}}

Where, x_{f}= final position

x_{i} = initial position

Put the value into the formula

v_{avg}=\dfrac{1.25+0}{0.5}

v_{avg}=2.5\ m/s

Hence, (I). The speed of apple is 5 m/s.

(II). The average velocity during 0.5 sec is 2.5 m/s

(III). The height of the branch of the tree from the ground is 1.25 m.

7 0
3 years ago
A cork able to float on water because it is
Schach [20]
A cork is less dense
8 0
3 years ago
Engineers can determine properties of a structure that is modeled as a damped spring oscillator, such as a bridge, by applying a
Kazeer [188]

The value of spring constant and the oscillator's damping constant is

K= 6605.667008, b= 0.002884387

Explanation:

For Weakly damping spring oscillator

K/m = W_0^2     (at resonance)

K= mW_0^2

=0.206 * ( 2π * 28.5) ^2

=0.206 * (2π)^2 * (28.5)^2

K= 6605.667008

F = - bV

b= -F/V = -F/ -W_0 * m

=F/W_0 * m

= 0.438N / 2π * 28.5 * 0.848

b= 0.002884387

8 0
3 years ago
100 N
weqwewe [10]

Answer:

The force required to move the cart is divided by three or 33.33 N.

Explanation:

8 0
3 years ago
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