Answer:
128 g of Li will react with 86.1 g of N₂ to completely consume it.
Solution:
The balance chemical equation is as follow,
<span> 6 Li + N</span>₂ → 2 Li₃<span>N
According to this equation,
28 g (1 mole) N</span>₂ reacts with = 41.64 g (6 moles) of Li
So,
86.1 g of N₂ will react with = X g of Li
Solving for X,
X = (86.1 g × 41.64 g) ÷ 28 g
X = 128 g of Li
<span>Answer:
1/4 is the average bond order for a pâ’o bond (such as the one shown in blue) in a phosphate ion.</span>
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