Question

It given that sin(-x) = -m where x is acute angle . express sec x in terms of m​

Answer 1

Answer:

$\sec(x)=\frac{1}{\sqrt{1-m^2}}$

Step-by-step explanation:

We know that:

$\sin(-x)=-m$

First, since sine is an odd function, we can move the negative outside:

$=-\sin(x)=-m$

Divide both sides by -1:

$\sin(x)=m$

We will now use the Pythagorean Identity:

$\cos^2(x)+\sin^2(x)=1$

Substitute m for sine:

$\cos^2(x)+m^2=1$

Solve for cosine:

$\cos^2(x)=1-m^2$

Take the square root of both sides:

$\cos(x)=\pm\sqrt{1-m^2}$

Since x is an acute angle, cosine will always be positive. Thus:

$\cos(x)=\sqrt{1-m^2}$

Take the reciprocal of both sides. Hence:

$\frac{1}{\cos(x)}=\sec(x)=\frac{1}{\sqrt{1-m^2}}$