Hi There! :)
Active <span>transport requires the use of energy. :)
Therefore A</span>
<h3>
Answer:</h3>
28 mol CaF
<h3>
General Formulas and Concepts:</h3>
<u>Math</u>
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Chemistry</u>
<u>Atomic Structure</u>
- Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.
<u>Stoichiometry</u>
- Using Dimensional Analysis
<h3>
Explanation:</h3>
<u>Step 1: Define</u>
[Given] 1.7 × 10²⁵ molecules CaF
[Solve] moles CaF
<u>Step 2: Identify Conversions</u>
Avogadro's Number
<u>Step 3: Convert</u>
- [DA] Set up:

- [DA] Multiply/Divide [Cancel out units]:

<u>Step 4: Check</u>
<em>Follow sig fig rules and round. We are given 2 sig figs.</em>
28.2298 mol CaF ≈ 28 mol CaF
I’m don’t kill me if I’m wrong but I think it’s high melting point
Answer:
Ratio is 3:2
3CO = 2Fe or 1.5 CO = 1 Fe
Explanation:
Fe2O3 + 3CO = 2Fe + 3CO2
Fe2O3 = Iron (|||) oxide
CO = Carbon monoxide
Fe = Solid Iron
CO2 = Carbon dioxide
Excellent is already balanced.
10 Moles Fe and 15 Moles of CO2
5 Moles Fe2O3 + 15 Moles 3CO = 10 Moles Fe + 15 Moles 3CO2
What is the ratio of carbon monoxide to solid iron
Ratio is 3:2 or 1.5 CO = 1 Fe