Reactivity I am sure about this answer
Answer:
Explanation:
Given:
length of unstrained spring,
mass attached to the spring,
length of the spring after hanging the mass,
energy to be stored in the spring,
<u>The length of the spring stretched after hanging the mass:</u>
<u>Therefore the stiffness constant of the spring:</u>
where
F = is the force to which the spring is subjected for the corresponding change in length .
here,
<u>As we know that the spring potential energy is given as:</u>
where
extension in the length of the spring
<u>So the total length of the spring when it stores 10 J energy:</u>
Answer:
0.76 rad/s^2
Explanation:
First, we convert the original and final velocity from rev/s to rad/s:
Now, we need to find the number of rads that the tire rotates in the 250m path. We use the arc length formula:
Now, we just use the formula:
Answer:
Q = 0.24
Explanation:
given data:
resonant angular frequency is given as \omega_O = \frac{1}{\sqrt{LC}}
where L is inductor = 150 mH
C is capacitor = 0.25\mu F
QUALITY FACTOR is given as
Putting all value to get quality factor value
Q =
Q = 0.24
<span>C. From positive to negative terminals
Hope this helps!</span>