Answer:
Quick maths
First you find the fafarick and the lalickc and the caprisum and the joinnt
Answer:
The kinetic energy is 86.6 zepto joules.
Explanation:
Given that,
Number of orbit n =5
We know that,
Bohr's radius for hydrogen atom is

Now, put the value of n in the formula of radius


We need to calculate the kinetic energy
Using formula of kinetic energy

Put the value into the formula


We know that,

The kinetic energy is


Hence, The kinetic energy is 86.6 zepto joules.
Answer:
Notebook paper makes paper airplane fly farther
Explanation:
It's because paper airplane made of notebook is lighter and can fly far.
Answer: f = 927.55Hz
Explanation: Since the the tube is open-closed, the length of air and the wavelength of sound passing through the tube is given below
L = λ/4 where λ = wavelength.
speed of sound in air = v = 343m/s.
fundamental frequency of open closed tube = 315Hz
λ = 4L.
v = fλ
343 = 315 * 4L
343 = 1260 * L
L = 343/ 1260
L = 0.27m
In the same tube of length L = 0.27m but different medium ( helium), the speed of sound is 1010m/s.
The length of tube and wavelength are related by the formulae below
L = λ/4, λ=4L
λ = 4 * 0.27
λ = 1.087m.
v = fλ
1010 = f * 1.087
f = 1010/1.807
f = 927.55Hz
Answer:
Pressure = ρgh
pressure (p) is measured in pascals (Pa)
density (ρ) is measured in kilograms per metre cubed (kg/m3)
The fore of gravitational field strength (g) is measured in N/kg or m/s 2
height of column (h) is measured in metres (m)
Answer = 235,200 Pa
Explanation:
Pressure = ρgh
Pressure = 1,000 x 9.8 x 24
Pressure = 235,200 Pa