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pochemuha
3 years ago
12

At 39 °C, a gas occupies 45.5 mL. If the temperature is cooled to 2 °C,

Chemistry
1 answer:
denis-greek [22]3 years ago
8 0
I think it should be none of those
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The answer to the selected question is Flurione

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A student is doing an experiment to determine the effects of temperature on an object. He writes down that the initial temperatu
bogdanovich [222]

Answer:

1) The Kelvin temperature cannot be negative

2) The Kelvin degree is written as K, not ºK

Explanation:

The temperature of an object can be written using different temperature scales.

The two most important scales are:

- Celsius scale: the Celsius degree is indicated with ºC. It is based on the freezing point of water (placed at 0ºC) and the boiling point of water (100ºC).

- Kelvin scale: the Kelvin is indicated with K. it is based on the concept of "absolute zero" temperature, which is the temperature at which matter stops moving, and it is placed at zero Kelvin (0 K), so this scale cannot have negative temperatures, since 0 K is the lowest possible temperature.

The expression to convert from Celsius degrees to Kelvin is:

T(K)=T(^{\circ}C)+273.15

Therefore  in this problem, since the student reported a temperature of -3.5 ºK, the errors done are:

1) The Kelvin temperature cannot be negative

2) The Kelvin degree is written as K, not ºK

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4 years ago
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Balance each skeleton reaction, use Appendix D to calculate E°cell, and state whether the reaction is spontaneous:(b) Hg₂²⁺(aq)
Olegator [25]

The given reaction is not spontaneous.

We must recognize changes in oxidation states that take place across elements in order to balance these equations. To accomplish this, keep in mind following guidelines:

A neutral element on its own has an oxidation number of zero.For a neutral molecule, the total number of oxidations must be zero.The net charge of an ion is equal to the sum of its oxidation numbers.In a compound: hydrogen prefers +1, oxygen prefers -2, fluorine prefers -1.In a compound with no oxygen present the other halogens will also prefer -1.

One of the mercury atoms is oxidized from +1 to +2 in the simple aqueous ion, for a loss of 1 electron.

Oxidation half-reaction:

0.5 Hg^{2+} _{2} (aq) →Hg^{2+} (aq) + 1e^-

E^o _{ox} = - 0.92 V

The other mercury is reduced from +1  to zero in mercury metal, for a gain of 1 electron.

Reduction half-reaction:

0.5 Hg^{2+} _{2} (aq) + 1 e^- →Hg(l)

E^o _{red} = 0.85V

This is a disproportionation redox reaction !

Net reaction:

Hg^{2+} _{2} (aq) →Hg^{2+} (aq) + Hg (l)

E^o _{cell} = 0.85 - 0.92 = -0.07V

The cell potential is negative so this reaction is NOT spontaneous.

To learn more about the non spontaneous reaction please click on the link brainly.com/question/20358734

#SPJ4

5 0
2 years ago
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