At 39 °C, a gas occupies 45.5 mL. If the temperature is cooled to 2 °C,
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Answer: 8.28g Na
Explanation: use ideal gas law
PV= nRT
Solve for moles of Cl2
n= PV/ RT
Substitute:
= 1 atm x 4.0 L / 0.08205 L.atm/ mol. K x 273 K
= 0.18 moles Cl2
Do stoichiometry to solve for m of Na
2 Na + Cl2 => 2 NaCl2
=0.18 moles Cl2 x 2 mol Na/ 1 mol Cl2 x 23g Na / 1 mol Na
= 8.28 g Na.
Covalent bond forms between the oxygen and hydrogen atoms.
(I attached a picture that could help)
-Hope that helps,
Good luck!
(I attached a picture that could help)
-Hope that helps,
Good luck!