ability to react with oxygen
Answer:
100Jkg/°C
Explanation:
Given parameters:
Mass of metal = 2kg
Amount of heat energy = 1600J
Initial temperature = 5°C
Final temperature = 13°C
Unknown:
Specific heat capacity of the metal = ?
Solution:
Specific heat capacity of a body is the amount of heat needed to raise the temperature of unit mass of a body by 1°C.
H = m x C x (T₂ - T₁ )
H is the amount of heat
m is the mass
C is the unknown specific heat capacity
T is the temperature
Insert the parameters and solve;
1600 = 2 x C x (13 - 5)
1600 = 16C
C = 100Jkg/°C
<h3>Answer:</h3>
We will neither give the Hypertonic Solution nor the Isotonic Solution but the patient will be given an Hypotonic Solution.
<h3>Explanation:</h3>
As the patient is taken for heat stroke and has resulted in dehydration so it means that the water content in the cells of the patient has been decreased and the solute content is being increased. Hence, this case is known as <em>Hypertonicity</em>. So, in order to make the concentration of water and solute balance (<em>Isotonicity</em>) on both sides (inside and outside the cells) we should administer an <em>Hypotonic solution</em> into the patient body. Therefore, the higher concentration of solutes in cells will drag the water content from hypotonic solution and gradually the process will attain an isotonic environment.
Step 1. - Scientists first take a look at their empirical evidence and try to explain it.
Step 2. - Scientists test if their explanation or conclusion is logical.
Step 3. - If their explanation is logical, they search for new test that may help them to support their first idea.
In sodium carbonate I believe the carbonate is considered the base and that the HCl will react with the carbonate to produce bicarbonate (HCO₃). Due to that, I think the chemical equation should be HCl+NaCO₃→HCO₃+NaCl.
To neutralize the solution, you need to have equal amounts H⁺ and CO₃⁻ which means that you need to have equal amounts HCl and NaCO₃. To find this you need to know how many moles of NaCO₃ there are in the 25mL solution since that is the number of moles of HCl you need. You would then divide the number of moles of HCl needed by 2M to find the volume of HCl needed.
With the information given I don't think you can answer this. You need to know what the concentration of the sodium carbonate is and with out that value you can't determine how many moles of sodium carbonate there are. You need to know how many moles of sodium carbonate you have in order to know how much 2M hydrochloric acid is needed to neutralize it.
The process you would usually use is:
(0.025L NaCO₃)×(molarity of NaCO₃)=moles NaCO₃
moles NaCO₃=moles HCl needed to neutralize
(moles HCl needed to neutralize)/2M=Liters of HCl needed to neutralize
Let me know if the question came with any more information but right now I don't think it can be solved.
I hope this helps. Let me know if anything is unclear.
Also, since this reaction is between a strong acid and weak base, when you neutralize it with the strong acid the pH of the solution will not be 7. It will most likely be under seven since HCO₃ is being produced which is the conjugate acid of CO₃ and therefore create a slightly acidic solution at the equivalence point (the equivalence point is another way of saying the solution was neutralized). You probably don't need to know this for the scope of your class but I thought it was worth mentioning since later on you will have to deal with this fact.