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2 years ago

How is a "decay event' recorded

1 answer:

6 0

Their dark matter detector witnessed the rarest event ever recorded: the radioactive decay of xenon-124. ... The supreme fine-tuning and clean measurements allowed by XENON1T enabled scientists to witness xenon-124 decay away at a rate that far exceeds the life of the universe.
Hope that helps.

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1.) The process for converting ammonia to nitric acid involves the conversion of NH3 to

Firdavs [7]

Answer:

a) 1.39 g ; b) O₂ is limiting reactant, NH₃ is excess reactant; c) 0.7 g

Explanation:

We have the masses of two reactants, so this is a limiting reactant problem.

We will need a balanced equation with masses, moles, and molar masses of the compounds involved.

1. Gather all the information in one place with molar masses above the formulas and masses below them.

MM: 17.03 32.00 30.01

4NH₃ + 5O₂ ⟶ 4NO + 6H₂O

Mass/g: 1.5 1.85

2. Calculate the moles of each reactant

$\text{moles of NH}_{3} = \text{1.5 g NH}_{3} \times \dfrac{\text{1 mol NH}_{3}}{\text{17.03 g NH}_{3}} = \text{0.0881 mol NH}_{3}\\\\\text{moles of O}_{2} = \text{1.85 g O}_{2} \times \dfrac{\text{1 mol O}_{2}}{\text{32.00 g O}_{2}} = \text{0.057 81 mol O}_{2}$

3. Calculate the moles of NO we can obtain from each reactant

From NH₃:

The molar ratio is 4 mol NO:4 mol NH₃

$\text{Moles of NO} = \text{0.0881 mol NH}_{3} \times \dfrac{\text{4 mol NO}}{\text{4 mol NH}_{3}} = \text{0.0881 mol NO}$

From O₂:

The molar ratio is 4 mol NO:5 mol O₂

$\text{Moles of NO} = \text{0.057 81 mol O}_{2}\times \dfrac{\text{4 mol NO}}{\text{5 mol O}_{2}} = \text{0.046 25 mol NO}$

4. Identify the limiting and excess reactants

The limiting reactant is O₂ because it gives the smaller amount of NO.

The excess reactant is NH₃.

5. Calculate the mass of NO formed

$\text{Mass of NO} = \text{0.046 25 mol NO}\times \dfrac{\text{30.01 g NO}}{\text{1 mol NO}} = \textbf{1.39 g NO}$

6. Calculate the moles of NH₃ reacted

The molar ratio is 4 mol NH₃:5 mol O₂

$\text{Moles reacted} = \text{0.057 81 mol O}_{2} \times \dfrac{\text{4 mol NH}_{3}}{\text{5 mol O}_{2}} = \text{0.046 25 mol NH}_{3}$

7. Calculate the mass of NH₃ reacted

$\text{Mass reacted} = \text{0.046 25 mol NH}_{3} \times \dfrac{\text{17.03 g NH}_{3}}{\text{1 mol NH}_{3}} = \text{0.7876 g NH}_{3}$

8. Calculate the mass of NH₃ remaining

Mass remaining = original mass – mass reacted = (1.5 - 0.7876) g = 0.7 g NH₃

8 0

2 years ago

The development of new technology requires the evaluation of the overall benefit to cost ratio of the new technology.

avanturin [10]

Answer:

B and C Reduce Emissions and Least fuel economy

Explanation:

Plug-in electric vehicles are related, fun and practical (also called electric cars or hybrid electric vehicles). We will reduce emissions and save you even money. EVs deliver more than individual advantages. EVs will allow the US to have a more diverse range of transportation fuel options. Last year the US used almost nine billion barrels of oil, of which two-thirds went into shipping. We are vulnerable to price increases and supply disruptions because of our dependence upon oil. EVs help reduce this threat, as almost all US electricity, including coal, nuclear, natural gas and renewables, is generated from domestic sources.Vehicles can also minimize the CO2 emissions, improve health, and reduce environmental damage that contribute to climate change and smog. Charging your EV for renewable, such as solar or wind, will further reduce these emissions. Link to a calculator on the right to the pollution disparity between the traditional and an EV. Discover how EV reduce pollution and their emissions during their life cycle.

6 0

3 years ago

What is the relationship between the sun and the oceans?

zalisa [80]

The oceans store large amounts of energy

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3 years ago

Examples of conduction

Sonja [21]

Answer:

Conduction: Touching a stove and being burned. Ice cooling down your hand. Boiling water by thrusting a red-hot piece of iron into it.

Explanation:

3 0

2 years ago

2. A/an _______ bond allows metals to conduct electricity. A. ionic B. metallic C. covalent D. atomic

lisov135 [29]

The appropriate answer is b. A metallic bond allows metals to conduct electricity. Metallic bonds are formed by atoms of metals in which the outer electrons of the atoms from a common electron cloud. In metallic bonding the atoms are not used up in the actual bond but are shared so they are free to move about to conduct electricity. Electrons in the other bond types are held in place in the molecule an are not free to move about so they cannot conduct electricity.

7 0

2 years ago

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