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tankabanditka [31]
3 years ago
10

PLEASE HELP ME I WILL VOTE BRAINLIEST

Mathematics
1 answer:
Tju [1.3M]3 years ago
7 0

Answer: 60%.........................                                                                                                                                        

               

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what is the volume and surface area of a box that is 9.5 inches tall, 3.8 nches wide,and 4.2 inches long.
monitta
Assuming this is a rectangular prism, here are the formulas for the volume and surface area.
V=l×w×h
SA=lw+lw+lh+lh+wh+wh
I didn't want to give the answer away, but I wanted to head you in the right direction. Hope this helped!
5 0
3 years ago
If two angles of an isosceles triangle are congruent, then the sides opposite those angles are congruent. True or false?
inna [77]
It is true. It is an isosceles triagle
5 0
3 years ago
Abes apple orchard plans both green apple trees. This planting will include 21 red apple trees and 18 green apple trees. What is
Paha777 [63]

Answer:

The ratio of green apples to red apples is \frac{6}{7}.

Step-by-step explanation:

Given,

Number of red apples = 21

Number of green apples = 18

We have to find out the ratio of green apples to red apples.

Solution,

For finding the ratio we have to divide the number of green apples to the number of red apples.

So, we can frame the above sentence as;

Ratio=\frac{\textrm{number of green apples}}{\textrm{number of red apples}}

Now substituting the values, we get;

Ratio=\frac{18}{21}=\frac{6}{7}

Hence The ratio of green apples to red apples is \frac{6}{7}.

3 0
4 years ago
Help ASAP I’ll give brainliest
soldier1979 [14.2K]

Answer:

B

Step-by-step explanation:

<h2>—Math</h2>

–x/4 < 7

–x < 28

x > –28

<em>follow </em><em>my </em><em>account^</em><em>^</em>

4 0
3 years ago
Read 2 more answers
Alice, Bob, and Carl arrange to meet for lunch on a certain day. They arriveindependently at uniformly distributed times between
Svetllana [295]

Answer:

a. What is the probability that Carl arrives first?

Probability that Carl arrives first is ¹/₃ = 33.33% since their arrival times is uniformly distributed. The same probability applies to Bob and Alice.

b. What is the probability that Carl will have to wait more than 10 minutes for one of the others to show up?

Assuming that Carl arrived on time, 1:10 PM, we must determine the probability that Alice or Bob arrive between 1:20 and 1:30 (half the remaining time)

P = [3 · (¹/₂ - ¹/₃)] · [3 · (¹/₂ - ¹/₃)] = (3 · ¹/₆) · (3 · ¹/₆) = ¹/₂ · ¹/₂ = ¹/₄ = 25% chance that either Alice or Bob arrive more than 10 minutes later

c. What is the probability that Carl will have to wait more than 10 minutes for both of the others to show up?

P = 1 - 25% = 75%

d. What is the probability that the person who arrives second will have to wait more than 5 minutes for the third person to show up?

I divided the 20 minutes by 5 to get ¹/₄:

P (|S - T| ≤ ¹/₄) = {[(x + ¹/₄)²] / 2} + (1 / 2x) + {[(⁵/₄ - x)²] / 2} = 0.09375 + 0.25 + 0.09375 = 0.4375 = 43.75%

4 0
3 years ago
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