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3 years ago

What is the measure of angle Z?

Mathematics

1 answer:

Iteru [2.4K]3 years ago

3 0

Answer:

sum of exterior angles of polygon = 360°

therefore,

z = 360 - (105+145)

z = 360 - 250

z = 110°

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In the past you paid $800 per month to rent your apartment. You now pay $900 per month for your rent. What is the percent increa

Leni [432]

The percent increase is 12.5%, 800 multiplied by 0.125 equals 100 and 100+800=900.

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4 years ago

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ziro4ka [17]

Ha. That looks alot like i-ready. (i-ready sucks butt.)

But the horror that is i-ready aside, your answer is the third one : The proportion of grandparents that feel safe entering their account information online is 0.32.

32% converted to a decimal is 0.32, and 68% converted to a decimal is 0.68. That would mean that the proportion for grandparents that feel safe doing so is 0.32, and the number of grandparents that don't feel safe doing so is 0.68.

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3 years ago

Help worth a lot of pounts

Anton [14]

Answer:

See below.

Step-by-step explanation:

Let x = amount of money you have in your account.

The money in your account plus the $125 extra that you need equals the total cost of the computer.

The equation is:

x + 125 = 2250

Now we solve the equation by subtracting 125 from both sides.

x = 2125

Answer: You have now $2125 in your account

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3 years ago

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The zeros of a quadratic function are -8 and 5. Write the quadratic function in Standard Form.

nataly862011 [7]

Answer:

y = x² + 3x - 40

Step-by-step explanation:

Given the zeros are x = - 8 and x = 5, then the factors are

(x + 8) and (x - 5) and

y = (x + 8)(x - 5) ← expand factors

y = x² - 5x + 8x - 40, hence

y = x² + 3x - 40 ← in standard form

7 0

3 years ago

A 100 gallon tank initially contains 100 gallons of sugar water at a concentration of 0.25 pounds of sugar per gallon suppose th

Vsevolod [243]

At the start, the tank contains

(0.25 lb/gal) * (100 gal) = 25 lb

of sugar. Let $S(t)$ be the amount of sugar in the tank at time $t$ . Then $S(0)=25$ .

Sugar is added to the tank at a rate of P lb/min, and removed at a rate of

$\left(1\frac{\rm gal}{\rm min}\right)\left(\dfrac{S(t)}{100}\dfrac{\rm lb}{\rm gal}\right)=\dfrac{S(t)}{100}\dfrac{\rm lb}{\rm min}$

and so the amount of sugar in the tank changes at a net rate according to the separable differential equation,

$\dfrac{\mathrm dS}{\mathrm dt}=P-\dfrac S{100}$

Separate variables, integrate, and solve for S.

$\dfrac{\mathrm dS}{P-\frac S{100}}=\mathrm dt$

$\displaystyle\int\dfrac{\mathrm dS}{P-\frac S{100}}=\int\mathrm dt$

$-100\ln\left|P-\dfrac S{100}\right|=t+C$

$\ln\left|P-\dfrac S{100}\right|=-100t-100C=C-100t$

$P-\dfrac S{100}=e^{C-100t}=e^Ce^{-100t}=Ce^{-100t}$

$\dfrac S{100}=P-Ce^{-100t}$

$S(t)=100P-100Ce^{-100t}=100P-Ce^{-100t}$

Use the initial value to solve for C :

$S(0)=25\implies 25=100P-C\implies C=100P-25$

$\implies S(t)=100P-(100P-25)e^{-100t}$

The solution is being drained at a constant rate of 1 gal/min; there will be 5 gal of solution remaining after time

$1000\,\mathrm{gal}+\left(-1\dfrac{\rm gal}{\rm min}\right)t=5\,\mathrm{gal}\implies t=995\,\mathrm{min}$

has passed. At this time, we want the tank to contain

(0.5 lb/gal) * (5 gal) = 2.5 lb

of sugar, so we pick P such that

$S(995)=100P-(100P-25)e^{-99,500}=2.5\implies\boxed{P\approx0.025}$

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3 years ago