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3 years ago

12

PLZ HELP I AM FAILING!!! John wanted to paint the walls of his bedroom. His bedroom is a rectangular prism. The dimensions of hi

s room are shown in the diagram.
--Surface Area of Rectangular Prisms Asynchronous Practice--

2 answers:

statuscvo [17]3 years ago

7 0

Answer:

Step-by-step explanation:

avanturin [10]3 years ago

3 0

Add all of the sides together and get your total my guy!!

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Two trials are conducted for an experiment. In Trial A, the measured value is 240, while the actual value is 200. In Trial B, th

Zepler [3.9K]

Answer:

A is the answer 456% and 512%

Step-by-step explanation:

Percent Errors

Trial A

Trial B

Measured Value

240

195

Actual Value

200

240

Percent Error

?

?

Complete the table.

Percent Errors

Trial A

Trial B

Measured Value

240

195

Actual Value

200

240

Percent Error

440440%

435435%

5 0

2 years ago

ASAP BRAINLIEST !! Luis is given the fraction 4/5. He is told to create an equivalent fraction with a numerator of 32. Explain t

solniwko [45]

Answer: answer 40.

Step-by-step explanation:

Note : lets make x the missing denominator.

I would take the 4/5 and set it equals to 32/x

we then cross multiply

where it would be 4 * x = 32 * 5

it would then be 4x = 160

we would then divide 160 by 4

x = 160/ 4

and x would be 40

.... therefore the missing denominator is 40.

8 0

3 years ago

Read 2 more answers

What is the distance between -10 and six on a number line

Mkey [24]

Answer:

10+6=16

Step-by-step explanation:

3 0

3 years ago

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Past records indicate that the probability of online retail orders that turn out to be fraudulent is 0.08. Suppose that, on a gi

Sunny_sXe [5.5K]

Answer:

The probability that there are 2 or more fraudulent online retail orders in the sample is 0.483.

Step-by-step explanation:

We can model this with a binomial random variable, with sample size n=20 and probability of success p=0.08.

The probability of k online retail orders that turn out to be fraudulent in the sample is:

$P(x=k)=\dbinom{n}{k}p^k(1-p)^{n-k}=\dbinom{20}{k}\cdot0.08^k\cdot0.92^{20-k}$

We have to calculate the probability that 2 or more online retail orders that turn out to be fraudulent. This can be calculated as:

$P(x\geq2)=1-[P(x=0)+P(x=1)]\\\\\\P(x=0)=\dbinom{20}{0}\cdot0.08^{0}\cdot0.92^{20}=1\cdot1\cdot0.189=0.189\\\\\\P(x=1)=\dbinom{20}{1}\cdot0.08^{1}\cdot0.92^{19}=20\cdot0.08\cdot0.205=0.328\\\\\\\\P(x\geq2)=1-[0.189+0.328]\\\\P(x\geq2)=1-0.517=0.483$

The probability that there are 2 or more fraudulent online retail orders in the sample is 0.483.

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3 years ago

Graph y= -2x+7. Help please

musickatia [10]

Answer:

There you go fam, That website is really useful btw, you should use it, if u want ill give you the link, just comment

Step-by-step explanation:

4 0

3 years ago