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EleoNora [17]
3 years ago
15

A student wants to determine if a

Chemistry
1 answer:
Sauron [17]3 years ago
7 0

Answer:

The Density of Magnesium.

Explanation:

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What is the pOH of 0.5 M KOH?
jenyasd209 [6]

Answer:

pOH = 0.3

Explanation:

As KOH is a strong base, the molar concentration of OH⁻ is equal to the molar concentration of the solution. That means that in this case:

  • [OH⁻] = 0.5 M

With that information in mind we can<u> calculate the pOH </u>by using the following formula:

  • pOH = -log[OH⁻]
  • pOH = -log(0.5)
  • pOH = 0.3
5 0
2 years ago
Standard reduction potentials are based on which element?
Andreas93 [3]

Answer: option B. Hydrogen

Explanation:

6 0
3 years ago
Describe what happens in a collision??
3241004551 [841]

Answer:

The forces involved in a collision are equal in size and directed in the opposite direction, and they accelerate both objects. Each object accelerates equally in collisions with things of equal mass.

Explanation:

6 0
1 year ago
Find δs∘ for the reaction between nitrogen gas and hydrogen gas to form ammonia:12n2(g) 32h2(g)→nh3(g)
Dima020 [189]

Nitrogen (N2) and hydrogen (H2) gases react to form ammonia, which requires -99.4 J/K of standard entropy (ΔS°).

What is standard entropy?

The difference between the total standard entropies of the reaction mixture and the summation of the standard entropies of the outputs is the standard entropy change. Each entropy in the balanced equation needs to be compounded by its coefficient, as shown by the letter "n."

Calculation:

Balancing the given reaction following-

1/2 N₂(g) + 3/2 H₂ (g)→ NH₃ (g)

ΔS° = [1 mol x S° (NH₃)g] - [1/2 mol x S° (N₂)g] - [3/2 mol x S°(H₂)g]

Here S° = standard entropy of the system

Insert into the aforementioned equation all the typical entropy values found in the literature:

ΔS° = [1 mol x 192.45 J/mol.K] - [1/2 mol x 191.61 J/mol.K] - [3/2 mol x 130.684 J/mol.K]

⇒ΔS° = - 99.4 J/K

Therefore, the standard entropy, ΔS° is -99.4 J/K.

Learn more about standard entropy here:

brainly.com/question/14356933

#SPJ4

5 0
1 year ago
Choose the options below that are true.
Assoli18 [71]

Answer:

The options <u>(A) -</u>The rate law for a given reaction can be determined from a knowledge of the rate-determining step in that reaction's mechanism.  and <u>(C) </u>-The rate laws of bimolecular elementary reactions are second order overall ,<u>is true.</u>

Explanation:

(A) -The rate law can only be calculated from the reaction's slowest or rate-determining phase, according to the first sentence.

(B) -The second statement is not entirely right, since we cannot evaluate an accurate rate law by simply looking at the net equation. It must be decided by experimentation.

(C) -Since there are two reactants, the third statement is correct: most bimolecular reactions are second order overall.

(D)-The fourth argument is incorrect. We must track the rates of and elementary phase that is following the reaction in order to determine the rate.

<u>Therefore , the first and third statement is true.</u>

5 0
2 years ago
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