Could I hear the options..
A- Identify the mixture:
The mixture of powdered charcoal and powdered sugar is considered as a homogeneous mixture. This means that you cannot identify the components with naked eye as they are uniformly distributed in the mixture.
B- Separate components:
You ca separate the charcoal powder from the sugar powder using the following steps:
1- add water. Sugar will dissolve in water while charcoal won't.
2- filter the solution where the powdered charcoal will remain on the filter paper and the solution of powder will pass through.
3- boil the sugar solution (above 100 degrees celcius). The water will evaporate and the sugar will precipitate.
A is correct................
Answer:
H
Explanation:
Example,
HCl for hydrochloric acid
H2SO4 for sulphuric acid
HNO3 for nitric (v) acid
Answer : The value of
of the generic salt is, 
Explanation :
As we are given that, a solubility of salt is, 8.70 g/L that means 8.70 grams of salt present in 1 L of solution.
First we have to calculate the moles of salt 

Molar mass of
= 345 g/mol

Now we have to calculate the concentration of 
The equilibrium chemical reaction will be:

Concentration of
= 
Concentration of
= 
The solubility constant expression for this reaction is:
![K_{sp}=[A^{2+}][B^-]^2](https://tex.z-dn.net/?f=K_%7Bsp%7D%3D%5BA%5E%7B2%2B%7D%5D%5BB%5E-%5D%5E2)
Now put all the given values in this expression, we get:


Thus, the value of
of the generic salt is, 