A0 = 1
a1 = 2
a2 = 1
a3 = 2
This can be solved by guessing and checking and making sure that all atoms on the left side are accounted for on the right side. Both sides must have the same amount of atoms or the balancing is not correct.
One aluminum atom will cost 0.84 × 10⁻²³ cents.
Explanation:
Aluminium costs 85 cents per 453.592 grams.
number of moles = mass / atomic weight
number of moles of aluminium = 453.592 / 27 = 16.8 moles
To calculate the number of aluminum atoms we use the Avogadro's number:
if 1 mole of aluminum contains 6.022 × 10²³ aluminum atoms
then 16.8 moles of aluminum contains X aluminum atoms
X = (16.8 × 6.022 × 10²³) / 1 = 101.17 × 10²³ aluminum atoms
Now, taking in account the aluminium price, we devise the following reasoning:
if 101.17 × 10²³ aluminum atoms costs 85 cents
then 1 aluminum atom costs Y cents
Y = (1 × 85) / (101.17 × 10²³) = 0.84 × 10⁻²³ cents
Learn more about:
Avogadro's number
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