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Sergeu [11.5K]
3 years ago
8

Name the following compounds

Chemistry
2 answers:
TiliK225 [7]3 years ago
8 0
1 nitrogen hydrogen carbon oxygen
Ulleksa [173]3 years ago
7 0
1. Sodium hydrogen carbonate
2.Barium Chloride
3.Lithium Fluoride
4.Aluminum hydroxide
5.Strontium iodide

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Diethylene glycol is an organic compound used as a fuel in heating cans. Based on its structure and your data recorded in Data T
Firdavs [7]

Due to its higher oxygen content and based on its structure dietheylene glycol has a higher energy efficiency (cal/g) compared to isopropanol and paraffin wax.

<h3>What is the calorific value of a fuel?</h3>

The calorific value of a fuel is the amount of heat energy released from the combustion of the fuel under standard conditions.

Dietheylene glycol, isopropanol and paraffin wax are all used as fuels.

However, due to it higher oxygen content and based on its structure, diethethylene glycol has a higher calorific value than either isopropanol or paraffin wax.

Therefore, dietheylene glycol has a higher energy efficiency (cal/g) compared to isopropanol and paraffin wax.

Learn more about calorific value at: brainly.com/question/12975147

#SPJ1

7 0
2 years ago
Explain chemical equilibrium​
Agata [3.3K]

Answer:

chemical equilibrium, condition in the course of a reversible chemical reaction in which no net change in the amounts of reactants and products occurs. A reversible chemical reaction is one in which the products, as soon as they formed, react to produce the original reactants.

Explanation:

chemical equilibrium is the state in which both reactants and products are present in concentrations which have no further tendency to change with time, so that there is no observable change in the properties of the system.

6 0
2 years ago
Caluclate the number of grams of oxygen that must react
bonufazy [111]

Answer : The number of grams of oxygen react must be, 170.4 grams.

Solution : Given,

Mass of C_3H_8 = 46.85 g

Molar mass of C_3H_8 = 44 g/mole

Molar mass of O_2 = 32 g/mole

First we have to calculate the moles of C_3H_8.

\text{ Moles of }C_3H_8=\frac{\text{ Mass of }C_3H_8}{\text{ Molar mass of }C_3H_8}=\frac{46.85g}{44g/mole}=1.065moles

Now we have to calculate the moles of O_2

The balanced chemical reaction is,

C_3H_8+5O_2\rightarrow 3CO_2+4H_2O

From the balanced reaction we conclude that

As, 1 mole of C_3H_8 react with 5 mole of O_2

So, 1.065 moles of C_3H_8 react with 1.065\times 5=5.325 moles of O_2

Now we have to calculate the mass of O_2

\text{ Mass of }O_2=\text{ Moles of }O_2\times \text{ Molar mass of }O_2

\text{ Mass of }O_2=(5.325moles)\times (32g/mole)=170.4g

Therefore, the number of grams of oxygen react must be, 170.4 grams.

8 0
3 years ago
How many hydrogen moles are in 2.5 moles of aspartame c14h18n2o5
STALIN [3.7K]
Firstly, we need to convert 3g aspartame into moles aspartame. In order to do this we have to find the molecular mass of aspartame (the total weight of each atom of the molecule combined. This figure can be used to construct a conversion factor so that the grams may be converted into moles. Molecular weights for each atom can be found on any periodic table. Avagadro's number (6.022*10^23) is a constant value that expresses the number of molecules in one mole of a substance. 

The molecular weight for aspartame is 294.3 grams per mole. 

The process of finding how many atoms of H there are in 3.00g of aspartame would be like this: 

1. 3g * 1mol/294.3g = .01mol aspartame (this is converting grams to moles) 

2. .01mol * 6.022*10^23 = 6.022*10^21 (This is finding the number of molecules) 

3. (6.022*10^21) * 18 = 1.08*10^23 

This 3rd calculation is done because in part 2, you calculated the number of molecules of aspartame there were in 3g. In each molecule of aspartame there are 18 hydrogen atoms. So the final answer is: 
1.08*10^23 hydrogen atoms.
3 0
3 years ago
What temperature kelvin would .97mol of gas be to occupy 26L at 751.2mmHg?
crimeas [40]

Answer: 322.56 Kelvin

Explanation:

Use the Ideal Gas Law

PV=nRT

R is the gas constant

T is the temperature in Kelvins

P is the pressure in atmospheres

V is the volume in liters

n is the number of moles of gas

First, the mm of mercury need to be converted to atmospheres using the conversion factor 1atm = 760 torr.

751.2mmHg (torr) =0.988atm

Now plug everything in

(0.988)(26)=(0.97)(0.0821)T\\T=322.56K

5 0
3 years ago
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